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konstantin123 [22]
3 years ago
10

Which family in the periodic table has elements that are all radioactive

Chemistry
2 answers:
spayn [35]3 years ago
6 0
It would be Halogens.
DIA [1.3K]3 years ago
5 0

<u><em>Halogens Is correct</em></u>, in lesson 3.02 you are told "The halogens are known for their high reactivity as nonmetals. They are more willing to bond with lots of different substances. Many of the members of the halogen family go through phase changes (solid, liquid, gas) at room temperature." I believe it's Halogens.

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If an element has 10 protons and 11 neutrons and 10 electrons, which expression correctly identifies the element?
Sunny_sXe [5.5K]
When the number of protons and electrons are equal, that means the element is neutral. So, to know the element, find the element with an atomic number of 10. That would be Neon. Next, solve the mass number.

Mass number = protons +neutrons = 10+11 = 21

Thus, the expression should be written as shown in the attached picture.

6 0
3 years ago
A confused student was doing an isomer problem and listed the following six names as different structural isomers of C7H16. a. 1
klasskru [66]

In case of heptane (C7H16) the following structural isomers are possible

shown in figure

a. 1-sec-butylpropane : this is actually 3-methyl hexane

b. 4-methylhexane : this is actually 3-methylhexane

c. 2-ethylpentane : this is actually 3-methyl hexane

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f. 4-ethylpentane: This is actually 3-methylhexane

Hence all represent single isomer

4 0
3 years ago
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Answer:

65 million years ago there was a mass extinction that is best known for killing the dinosaurs. There was also a large

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ok done. Thank to me :>

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3 years ago
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You prepare a standard by weighing 10.751 mg of compound X into a 100 mL volumetric flask and making to volume. You further dilu
ArbitrLikvidat [17]

Answer:

0.12693 mg/L

Explanation:

First we <u>calculate the concentration of compound X in the standard prior to dilution</u>:

  • 10.751 mg / 100 mL = 0.10751 mg/mL

Then we <u>calculate the concentration of compound X in the standard after dilution</u>:

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Now we calculate the<u> concentration of compound X in the sample</u>, using the <em>known concentration of standard and the given areas</em>:

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Finally we <u>calculate the concentration of X in the sample prior to dilution</u>:

  • 0.012693 mg/L * 50 mL / 5 mL = 0.12693 mg/L
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3 years ago
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