Answer:

Explanation:
We are given that
Surface area of membrane=
Thickness of membrane=
Assume that membrane behave like a parallel plate capacitor.
Dielectric constant=5.9
Potential difference between surfaces=85.9 mV
We have to find the charge resides on the outer surface of membrane.
Capacitance between parallel plate capacitor is given by

Substitute the values then we get
Capacitance between parallel plate capacitor=

V=


Hence, the charge resides on the outer surface=
Answer:
3°C
Explanation:
We can that heat Q=m
dT
Where m is the mass
= specific heat capacity
dT = Temperature difference
here we have given m=625 g =.625 kg
specific heat of granite =0.79 J/(g-K) = 0.79 KJ/(kg-k)
=25°C
we have to find
we have also given Q=10.9 KJ
10.9=0.625×0.79×(25-
)
25-
=22
=3°C
U=1/2kx2
This image sums it up
Answer:
The distance between the two objects must be squared.
Explanation:
Gravitational force always act between two objects that have mass. The gravitational force is a weak force and attractive in nature.
The force of pull depends on the masses of the two objects and the distance between them.
The formula to calculate gravitational force between two objects having masses 'm' and 'M' and separated by a distance 'd' is given as:

Where, 'G' is called the universal gravitational constant and its value is equal to
.
Now, from the above formula, it is clear that, the force of gravitation is inversely proportional to the square of the distance between the two objects.
Thus, the quantity that must be squared in the equation of gravitational force between two objects is the distance 'd'.
Answer:
a. El tiempo de recorrido es
segundos para un objeto localizado a un metro de distancia de la cámara fotográfica.
b. El tiempo de recorrido es 0.118 segundos para un objeto localizado a un metro de distancia de la cámara fotográfica.
Explanation:
El sonido es un tipo de onda mecánica, que es un tipo de onda que necesita de un medio material para propagarse. En este caso, entendemos que el sonido se propaga a través del aire atmosférico hasta llegar a su destino y devolverse a rapidez constante. Entonces, podemos estimar el tiempo (
), medido en segundos, a partir de la siguiente fórmula:

Donde:
- Distancia entre la cámara fotográfica y el objeto, medida en metros.
- Rapidez del sonido en el aire atmosférico, medida en metros por segundo.
A continuación, calculamos el tiempo de recorrido:
a. (
,
)


El tiempo de recorrido es
segundos para un objeto localizado a un metro de distancia de la cámara fotográfica.
b. (
,
)


El tiempo de recorrido es 0.118 segundos para un objeto localizado a un metro de distancia de la cámara fotográfica.