All categories

3 years ago

Juan lives 100 m away from Bill/ What is Juan's average speed if he reaches Bill's home in 50 s?

1 answer:

3 0

Data:
ΔS (Total Distance Covered<span>) = 100 m
</span>ΔT (Total time taken<span>) = 50 s
Savg (</span><span>Average Speed) = ? (m/s)
</span><span>
Formula:
</span> $S_{Avg} = \frac{\Delta\:S}{\Delta\:T}$ <span>

Solving:
</span> $S_{Avg} = \frac{\Delta\:S}{\Delta\:T}$
$S_{Avg} = \frac{100}{50}$
$\boxed{\boxed{S_{Avg} =2\:m/s}}\end{array}}\qquad\quad\checkmark$ <span>

</span>

You might be interested in

The change in momentum of an object is equal to the Question 4 options: Force acting on it times its velocity. impulse acting on

lesya [120]

Answer:

impulse acting on it

Explanation:

The impulse is defined as the product between the force applied to an object (F) and the time interval during which the force is applied ( $\Delta t$ ):

$I=F\Delta t$

We can prove that this is equal to the change in momentum of the object. In fact, change in momentum is given by:

$\Delta p = m \Delta v$

where m is the mass and $\Delta v$ is the change in velocity. Multiplying and dividing by $\Delta t$ , we get

$\Delta p = m \frac{\Delta v}{\Delta t} \Delta t$

and since $\frac{\Delta v}{\Delta t}$ is equal to the acceleration, a, we have

$\Delta p = ma \Delta t$

And since the product (ma) is equal to the force, we have

$\Delta p = F \Delta t$

which corresponds to the impulse.

5 0

3 years ago

Sam is observing the velocity of a car at different times. After two hours, the velocity of the car is 50 km/h. After six hours,

Xelga [282]

A )
t 1 = 2 h, t 2 = 6 h
Δ t = t 2 - t 1 = 6 - 2 = 4 h
54 = 50 + a Δ t
54 = 50 + 4 a
4 a = 54 - 4
4 a = 4
a = 4 : 4
a = 1 km/h²
v o = 48 km/h
An equation that can be used to describe the velocity of the car at the different times is:
v = 48 + t
B ) The graph is in the attachment.

Download docx

6 0

2 years ago

What is the strength of the electric field ep 0.90 mm from a proton?

dem82 [27]

The electric field strength is inversely related to the square of the distance.so the strength of the electric field is given by

$E=\frac{1}{4\pi \epsilon _{0} } \frac{q}{r^{2} } = \frac{k q}{r^{2} }$

Here, $\frac{1}{4\pi \epsilon _{0} } = k$ is constant depend upon medium and its value is $9.0 \times10^{9} \ N m^2/C^2$ and q is charge and r is the distance.

Given $r = 0.90 mm = 9.0 \times 10^{-4} m$ and we know the charge of proton, $q = 1.6\times 10^{-19} \ C$ .

Therefore,

$E=\frac{9.0 \times10^{9} \ N m^2/C^2 \times1.6\times 10^{-19} \ C }{(9.0 \times 10^{-4} m)^2} = 0.177 \times 10^{-2} \ N/C \\\\ E= 1.77 \times 10^{-3} N/C$

4 0

3 years ago

What voltage battery would you need to send 2.5A of current through a light bulb of resistance 3.6 ohm

nadezda [96]

<h3><u>Given</u> :</h3>

Current flow light bulb = 2.5 $\sf{A}$

Resistance of light bulb = 3.6Ω

We have to find voltage of battery $.$

<h3><u>Solution</u> :</h3>

➠ As per ohm's law, current flow through a conductor is directly proportional to the applied potential difference.

➝ V ∝ I

➝ <u>V = I × R</u>

Where, R is the resistance of conductor.

⇒ V = I × R

⇒ V = 2.5 × 3.6

⇒ <u>V = 9 volt</u>

8 0

2 years ago

The sunspot cycle is a pattern of solar activity where the average number of sunspots gradually _______________________________

zzz [600]

Answer:

option D

Explanation:

Sunspots are the spot that appears on the sun, this spot appears darker than the surrounding surface of the sun.

Sun magnetic field goes through a cycle and this cycle is called the Sunspot cycle. Every 11 years the magnetic field of the sun completely flips. This sunspot cycle affects activity on the surface of the sun.

Sunspot cycle is the pattern of solar activity where an average number of sunspot gradually increase and decrease.

Hence, the correct answer is option D

8 0

2 years ago