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oksian1 [2.3K]
4 years ago
12

Juan lives 100 m away from Bill/ What is Juan's average speed if he reaches Bill's home in 50 s?

Physics
1 answer:
yanalaym [24]4 years ago
3 0
Data:
ΔS (Total Distance Covered<span>) = 100 m
</span>ΔT (Total time taken<span>) = 50 s
Savg (</span><span>Average Speed) = ? (m/s)
</span><span>
Formula:
</span>S_{Avg} =  \frac{\Delta\:S}{\Delta\:T}<span>

Solving:
</span>S_{Avg} = \frac{\Delta\:S}{\Delta\:T}
S_{Avg} = \frac{100}{50}
\boxed{\boxed{S_{Avg} =2\:m/s}}\end{array}}\qquad\quad\checkmark<span>

</span>

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Given by the problem:

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Re=\frac{2*3}{1.215x10^{-5} } =493015.6,laminar

The boundary layer is equal to:

\delta=\frac{4.91*2}{493015.6^{0.5} } =0.000019ft

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C=\frac{1.328}{\sqrt{Re} } =\frac{1.328}{\sqrt{493015.6} } ==0.0019

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F=Cp\frac{v^{2} }{2} wL=0.0019*1.938*(\frac{3^{2} }{2} )(10*2)=0.329lbf

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