Answer:
It will double.
Explanation:
Newton's Law of Gravity states that , where G is the gravitational constant, <em>r</em> is the distance between the objects' centers, and and are the objects' masses. We just have simple math here: by doubling , we double the entire fraction. By doubling the entire fraction, we double the gravitational pull. Therefore, <em>Newton's Law of Gravity states that if the mass of one object doubles, the gravitational pull on a second object will </em><em>double</em><em>.</em>
I hope this helps you understand it! Have a great day, 'kay?
Answer:
1.05 N
Explanation:
K = 0.7 N/m
e = 1.5 m
F = ?
from Hooke's law of elasticity
F = Ke
= 0.7×1.5
= 1.05 N
Answer:
Part A:
Part B:
Part C:
Explanation:
Part A:
We will use the following kinematics equation:
Part B:
We will use the same kinematics equation:
Part C:
The total time takes is 2t.
So the train moves a distance of
And the car moves a distance in Part A and in Part B:
So the total distance that the car traveled is
The difference between the train and the car is
From the case we know that:
- The moment of inertia Icm of the uniform flat disk witout the point mass is Icm = MR².
- The moment of inerta with respect to point P on the disk without the point mass is Ip = 3MR².
- The total moment of inertia (of the disk with the point mass with respect to point P) is I total = 5MR².
Please refer to the image below.
We know from the case, that:
m = 2M
r = R
m2 = 1/2M
distance between the center of mass to point P = p = R
Distance of the point mass to point P = d = 2R
We know that the moment of inertia for an uniform flat disk is 1/2mr². Then the moment of inertia for the uniform flat disk is:
Icm = 1/2mr²
Icm = 1/2(2M)(R²)
Icm = MR² ... (i)
Next, we will find the moment of inertia of the disk with respect to point P. We know that point P is positioned at the arc of the disk. Hence:
Ip = Icm + mp²
Ip = MR² + (2M)R²
Ip = 3MR² ... (ii)
Then, the total moment of inertia of the disk with the point mass is:
I total = Ip + I mass
I total = 3MR² + (1/2M)(2R)²
I total = 3MR² + 2MR²
I total = 5MR² ... (iii)
Learn more about Uniform Flat Disk here: brainly.com/question/14595971
#SPJ4
Answer:
Explanation:
Given that,
g = 31 ft/s²
For every 1 lbf force, the compression is 1in
Then we can know the spring constant.
From Hooke's Law
F = Kx
K = F/x
K = 1/0.14
K = 7.143 lbf/in
Now, if the spring deflection is 1.8in
Then, the force applied is
F = kx
F = 7.143 × 1.8
F = 12.857 lbf
Now, this force is equal to the weight of the body
And weight of the body can be determined using.
W = mg
Therefore,
m = W/g
m = 12.857 / 31
m = 0.415 lb
The mass of the object is 0.415 pounds