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Tems11 [23]
3 years ago
5

which of the following is the correct si unit to use in measuring the mass of a boulder a. tons b. kilograms c. ounces d. pounds

Physics
2 answers:
Salsk061 [2.6K]3 years ago
7 0
B. kilograms iuyiuiuhikj
lana66690 [7]3 years ago
7 0

B: Kilograms, or A: tons. :)

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Now imagine that you are a haitian taptap driver and want a more comfortable ride. You decide to replace the springs with new sp
Zinaida [17]

k=  - f/x this is the formula for spring constants

4 0
3 years ago
A portable music player, operating with four 1.5 V cells connected in series, provides a resistance of 15 000 Ω. What amount of
nata0808 [166]

Answer:

Explanation:

Given that,

A portable music player is operating with 4 cell batteries connected in series, and each cell has a P.D of 1.5V.

Then,

Total potential difference is

P.D_total = V1 + V2 + V3 + V4

P.D_total = 1.5 + 1.5 + 1.5 + 1.4

P.D_total = 6V.

The music player provides a resistance of 15,000Ω

R = 15,000Ω

We want to find the current (I) flowing through the music player?

Using ohms law

V = IR

Where

V is the potential difference

I is the current

R is the resistance

Therefore,

I = V/R

I = 6 / 15,000

I = 4 × 10^-4 A

I = 0.4 × 10^-3 A

I = 0.4 mA.

So, 0.4mA is passing through the music player

7 0
3 years ago
Select the correct answer.
Sergeeva-Olga [200]

Answer:

All of the above.

Explanation:

All of these steps are useful towards getting a job.

8 0
2 years ago
What is the potential energy of a 5kg rock that is 7m high on a hill
Goryan [66]

Explanation:

Gravitational potential energy = mgh = (5)(9.81)(7) = 343.35J.

4 0
3 years ago
If points a and b are connected by a wire with negligible resistance, find the magnitude of the current in the 12.0 v battery.
Marizza181 [45]
V = I * R
Where V is the voltage, I is the current and R is the resistance. Using Ohm's law, you require resistance to find the current through the wire. Technically, if the wire has a resistance of 0, you will get infinite current. But this isn't possible. Maybe the negligible resistance refers to the battery's internal resistance - not the wire's resistance. 
7 0
3 years ago
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