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GuDViN [60]
3 years ago
14

An object is allowed to fall freely near the surface of a planet. The object has an acceleration due to gravity of 24 m/s2. How

far will the object fall during the first second?
Physics
1 answer:
Alborosie3 years ago
6 0

Answer:

12 m

Explanation:

The object is in uniformly accelerated motion, so the distance covered can be found using the following suvat equation:

s=ut+\frac{1}{2}at^2

where

s is the distance

u is the initial velocity

t is the time

a is the acceleration

For this problem,

g=24 m/s^2

and

u = 0, since we are considering the first second of motion

So, substituting t = 1 s, we find

s=0+\frac{1}{2}(24)(1)^2=12 m

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uranmaximum [27]

Explanation:

When a radioactive substance decays then the fast moving electrons emitted by it is known as beta ray. Basically, a number of beta particles are ejected by a beta ray.

Symbol of a beta particle is ^{0}_{-1}e. A beta ray is a natural decay of a radioactive element. As we know that opposite charges get attracted towards each other. So, a beta ray gets attracted towards a positively charged plate.

Therefore, we can conclude that following are the characterizes a beta ray:

  • a product of natural radioactive decay.
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8 0
3 years ago
If a car has an initial velocity of 20 m/s and accelerates at 2.0 m/s2 for 100 m, what is its final velocity?
rodikova [14]

Answer:

28.28 ms-1

Explanation:

v² = u² + 2as

v² = 20² + 2×2×100

v²= 800

v = 28.28 ms-1

3 0
3 years ago
Given: Saturated air changes temperature by 0.5°C/100 m. The air is completely saturated at the dew point. The dew point has bee
erma4kov [3.2K]

Answer:

Explanation:

Given

saturated air temperature by 0.5^{\circ}C/100 m

Dew point temperature is given by t=2^{\circ}C

Dew point is defined as the temperature after which air no longer to uphold the water vapor fuse with it and some water vapor may condense to a liquid.

air continues to rise for 1400 m

i.e. change in temperature would be \Delta t =\frac{0.5}{100}\times 1400=7^{\circ}C

Final temperature t_f

t_f+\Delta t=t

t_f=2-7=-5^{\circ}C

3 0
3 years ago
A roller coaster starts from rest at point a and continues to point b on a frictionless track. what best describes the changes i
saw5 [17]

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3 0
3 years ago
Read 2 more answers
A. How does doubling the height of the cylinder affect its GPE?
vampirchik [111]

The answer would be:

Doubling the height will increase the amount of Joules produced.


8 0
3 years ago
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