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GuDViN [60]
3 years ago
14

An object is allowed to fall freely near the surface of a planet. The object has an acceleration due to gravity of 24 m/s2. How

far will the object fall during the first second?
Physics
1 answer:
Alborosie3 years ago
6 0

Answer:

12 m

Explanation:

The object is in uniformly accelerated motion, so the distance covered can be found using the following suvat equation:

s=ut+\frac{1}{2}at^2

where

s is the distance

u is the initial velocity

t is the time

a is the acceleration

For this problem,

g=24 m/s^2

and

u = 0, since we are considering the first second of motion

So, substituting t = 1 s, we find

s=0+\frac{1}{2}(24)(1)^2=12 m

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I would carry a 25 pound box up 5 flights, because it is lighter. You will wear out faster carrying a 50 pound box up 3 flights.

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Most of the ________ deposits in Virginia are located in the Appalachian Plateau and the Valley and Ridge provinces. A) coal B)
Nesterboy [21]

Answer:d Iron

Explanation:

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At the point of fission, a nucleus of ^235 U that has 92 protons is divided into two smaller spheres, each of which has 46 proto
IrinaK [193]

Answer : F = 3.5\times10^{3}\ N

Explanation :

Given that

Radius of sphere r = 5.90\times 10^{-15}\ m

The distance between the centers of the two spheres is

r = 2\times 5.90\times 10^{-15}\ m

The charge of the sphere q = 46\times1.6\times10^{-19} C

The magnitude of the repulsive force between the charges pushing them a part is

Using coulomb law

F = \dfrac {kq_{1}q_{2}}{r^{2}}

F = \dfrac{9\times10^{9}\times (46\times1.6\times10^{-19})^{2}C^{2}}{2\times(5.90\times10^{-15})^{2}\ m^{2}}

F = 3501.3\ N

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Hence, this is the required solution.









3 0
3 years ago
Why do people delte your answer or the question on here i is new so idk can someone plz help?
natita [175]

they are prob deleting you answers/questions because you are violating the Terms of Use or the Community Guidelines.

if you want to know how to get around Brainly and know the rules you can read the

Terms or Use: brainly.com/pages/terms_of_use

and the

Community Guidelines: brainly.com/pages/community_guidelines

:)

5 0
3 years ago
A soccer ball is kicked from the ground with an initial speed v at an upward angle θ. A player a distance d away in the directio
LuckyWell [14K]

Answer:

U = √Rg/sin2θ

Explanation:

Using the formula for "range" in projectile motion to derive the average speed before the ball hits the ground.

Range is the distance covered by the body in the horizontal direction from the point of launch to the point of landing.

According to the range formula,

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Cross multiplying we have;

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Dividing both sides by sin2θ, we have;

U² = Rg/sin2θ

Taking the square root of both sides we have;

√U² = √Rg/sin2θ

U = √Rg/sin2θ

Therefore, his average speed if he is to meet the ball just before it hits the ground is √Rg/sin2θ

3 0
3 years ago
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