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hammer [34]
3 years ago
12

A cheetah can go from a state of resting to running at 20 m/s in just two seconds what is the cheetah's average acceleration?

Physics
2 answers:
Sunny_sXe [5.5K]3 years ago
8 0

It's C i believe.  To solve it we just take 20 and divide it by 2. Which gives us the average of 10 m/s

-Steel jelly

Oxana [17]3 years ago
4 0

The answer would be C. 10 m/s

Hope this helps

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Express the measurement 0.00000575 into scientific notation.
g100num [7]

Answer: = 5.75 × 10 -6

Explanation:

= 5.75 × 10-6

(scientific notation)

= 5.75e-6

(scientific e notation)

= 5.75 × 10-6

(engineering notation)

(millionth; prefix micro- (u))

= 0.00000575

(real number)

7 0
2 years ago
What is the formula to calculate the thickness of a test tube?​
Maslowich

Answer:

Having the inside dimensions (ID) and the outside dimensions (OD) will allow you to figure out the wall thickness on tubing. You would need to subtract the ID from the OD and then divide by two. This number is the wall thickness.

Explanation:

4 0
2 years ago
What is the Force acting on a ball if the mass of the ball is 2 kg and the acceleration of the ball is 5 m/s2?
hjlf

Answer:

please find attached file

Explanation:

5 0
3 years ago
What best explains whether bromine (Br) or neon (Ne) is more likely to form a covalent bond? On left, a purple circle labeled Br
blondinia [14]

Answer:

I believe the answer is Bromine forms covalent bonds because it has many electron shells, but neon has only two electron shells and is tightly bound to its electrons.

Explanation:

valence electrons are the outermost shell, so when you go through keeping that in mind it helps you find the right answer

6 0
3 years ago
A 1-oz bullet is traveling with a velocity of 1400 ft/s when it impacts and becomes embedded in a 5-lb wooden block. The block c
schepotkina [342]

   After impact velocity = 14.968 ft/s

Weight and mass of Bullet and wooden block:

Bullet: w = 1oz = 1/16 lb m = 0.001941 lb

wooden block : W = 5lb M = 0.15528 lb

velocity of block and bullet immediately after impact:

Σmv1 + ΣImp = mv2

Resolving vertical component

( m× v₀cos30⁰) + 0 = ( m+M) v'

v' = ( m× v₀cos30⁰)/ (m+M)

v' = 14.968 ft/s

Horizontal and vertical component of the impulse exerted by block on the bullet:

   Here we will apply the principle of impulse and momentum.

 Horizontal component:

          -mv₀ cos30⁰ + RxΔt  =0

                                 RxΔt = mv₀sin30⁰

                                          = 0.001941 × 1400sin30⁰

                                   RxΔt = 1.3587 lb.s

         Vertical component:

                           -mv₀cos30⁰  + RyΔt =  -mv'

                                     RyΔt = m( v₀cos30⁰-v')

                                     RyΔt = 0.001941(1400cos30⁰ - 14.968)

                                              = 2.32 lb.s

     Learn more about impact here:

            brainly.com/question/15008937

                  #SPJ4  

8 0
1 year ago
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