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lbvjy [14]
3 years ago
9

Boyle's Law states that when a sample of gas is compressed at a constant temperature, the pressure P and volume V satisfy the eq

uation PV = C, where C is a constant. Suppose that at a certain instant the volume is 400 cm3, the pressure is 160 kPa, and the pressure is increasing at a rate of 40 kPa/min. At what rate is the volume decreasing at this instant?
Physics
1 answer:
Zigmanuir [339]3 years ago
3 0

Answer:

100 cm^3/min

Explanation:

PV = C

V = 400 cm^3

P = 160 kPa

dP/dt = + 40 kPa/min

According to the question

PV = C

Differentiate both sides with respect to time

P x dV/dt + V x dP/dt = 0

160 x dV/dt = - 400 x 40

dV/dt = - 100 cm^3/min

The volume decreases by the rate of 100 cm^3/min.

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By definition, Ampere is a unit of current which is a measure of the amount of charge passing through a point in a circuit per unit  of time, with an equivalent charge of 1.602 x 10^(-19) Coulomb per electron. To determine the number of electrons passing through the heater, we use the definition of the current. We calculate as follows:

13.5 A = 13.5 C per second
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3 years ago
A charged particle moves in a circular path in a uniform magnetic field.Which of the following would increase the period of the
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Answer:

Increasing its charge

Increasing the field strength

Explanation:

For a charged particle moving in a circular path in a uniform magnetic field, the centripetal force is provided by the magnetic force, so we can write:

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Re-arranging for r

r=\frac{Tv}{2\pi}

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qvB = m \frac{Tv^3}{2\pi}

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T=\frac{2\pi q B}{m v^2}

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Potential Energy, PE = mass x gravity x change in height

Potential Energy, PE = 165 x 9.81 x 42 = 67,983 J (=67.98 kJ)

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