The farthest position the mouse reaches inside the tunnel is 4 meters into the tunnel.
From the graph,
The positions reached after,
5 s = 4 m
10 s = 2 m
20 s = 2 m
35 s = 3 m
40 s = 0 m
So the farthest position here is 4 m into the tunnel.
The rate of change of positions is displacement. So displacement will be change in initial and final positions divided by change in time.
s = Δx / Δt
Therefore, the farthest position the mouse reaches inside the tunnel is 4 meters into the tunnel.
To knw more about displacement
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The same braking force does work on these objects to slow them down. The work done is equal to their change in kinetic energy:
FΔx = 0.5mv²
F = force, Δx = distance traveled, m = mass, v = speed
Isolate Δx:
Δx = 0.5mv²/F
Calculate Δx for each object.
Object 1: m = 4.0kg, v = 2.0m/s
Δx = 0.5(4.0)(2.0)²/F = 8/F
Object 2: m = 1.0kg, v = 4.0m/s
Δx = 0.5(1.0)(4.0)²/F = 8/F
The two objects travel the same distance before stopping.
I barely do my own homework lol
Answer:
1.29649
488.08706 nm
231715700.28346 m/s
Explanation:
n denotes refractive index
1 denotes air
2 denotes solution
= 632.8 nm
From Snell's law we have the relation
Refractive index of the solution is 1.29649
Wavelength is given by
The wavelength of the solution is 488.08706 nm
Frequency is given by
The frequency is
The speed in the solution is 231715700.28346 m/s
4. KE increases by a factor of 16 is the answer
<u>Explanation:</u>
Kinetic energy = (1/2)mv² = 0.5 mv²
where
m = mass, and v = velocity.
So at 15 mph,
K
E = 0.5 m (15)
² = 112.5 m
And at 60 mph,
K
E = 0.5 m (60)² = 1800 m
m is the mass, and not meters.
So, 1800 m/112. 5 m = 16
16 times the Kinetic Energy.
