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Bess [88]
2 years ago
11

A hot-air balloon consists of a basket hanging beneath a large envelope filled with hot air. A typical hot-air balloon has a tot

al mass of 539 kg, including passengers in its basket, and holds 2.62 ✕ 103 m3 of hot air in its envelope. If the ambient air density is 1.27 kg/m3, determine the density (in kg/m3) of hot air inside the envelope when the balloon is neutrally buoyant. Neglect the volume of air displaced by the basket and passengers. HINT kg/m3
Physics
1 answer:
Deffense [45]2 years ago
4 0

Answer:

1.05045 kg/m³

Explanation:

\rho_a = Density of air = 1.26 kg/m³

\rho_{ha} = Density of hot air

m_a = Mass of balloon = 539 kg

g = Acceleration due to gravity = 9.81 m/s²

v = Volume of air in balloon = 2.62\times 10^3\ m^3

The net force on the balloon will be

F_n=(\rho_a-\rho_{ha})vg

Also

F_n=m_ag

\\\Rightarrow 549g=(\rho_a-\rho_{ha})vg\\\Rightarrow 549=(1.26-\rho_{ha})2.62\times 10^3\\\Rightarrow -\rho_{ha}=\frac{549}{2.62\times 10^3}-1.26\\\Rightarrow \rho_{ha}=1.05045\ kg/m^3

The density of hot air inside the envelope is 1.05045 kg/m³

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