1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sav [38]
4 years ago
8

If an item as a density of.63 g/mL, when placed in water the item will

Physics
1 answer:
sergij07 [2.7K]4 years ago
5 0

Float. This is because water has a density of 1 g/ml, so anything less than this will float.

You might be interested in
Which is the answer
gtnhenbr [62]

Answer:

A: the intensity

Explanation:

the closer the sound, the more intense it is. Think about the ambulance illustration in your text book (assuming you are using a physics textbook) : )

3 0
3 years ago
Read 2 more answers
hi everyone im learning about zodiac signs can u plz share urs and somethings u like to for ex im an aquarius and i sing and lik
maksim [4K]

Answer: Aquarius!!!!

Explanation:

6 0
3 years ago
Read 2 more answers
I have a doubt on heat and temperature. I need help with this science question and here the question: The water in a lake just r
Volgvan

Answer:

you can't go ice skating on it because if it just reached the temp then you need to wait for about 2 hours

Explanation:

5 0
3 years ago
A 0.50-kg mass attached to the end of a string swings in a vertical circle (radius 2.0 m). When the mass is at the highest point
il63 [147K]

Answer:

31.1 N

Explanation:

m = mass attached to string = 0.50 kg

r = radius of the vertical circle = 2.0 m

v = speed of the mass at the highest point = 12 m/s

T = force of the string on the mass attached.

At the highest point, force equation is given as

T + mg =\frac{mv^{2}}{r}

Inserting the values

T + (0.50)(9.8) =\frac{(0.50)(12)^{2}}{2}

T = 31.1 N

7 0
3 years ago
Read 2 more answers
Two 10-cm-diameter charged rings face each other, 21.0 cm apart. Both rings are charged to +40.0 nC. What is the electric field
Katyanochek1 [597]

Complete question:

Two 10-cm-diameter charged rings face each other, 21.0 cm apart. Both rings are charged to +40.0 nC. What is the electric field strength  at the midpoint between the two rings ?

Answer:

The electric field strength at the mid-point between the two rings is zero.

Explanation:

Given;

diameter of each ring, d = 10 cm = 0.1 m

distance between the rings, r = 21.0 cm = 0.21 m

charge of each ring, q = 40 nC = 40 x 10⁻⁹ C

let the midpoint between the two rings = x

The electric field strength  at the midpoint between the two rings is given as;

E_{mid} = E_{right} +E_{left}\\\\E_{right}  = \frac{KQ}{(x^2 + r^2)^\frac{2}{3} } \\\\E_{leftt}  = -\ \frac{KQ}{(x^2 + r^2)^\frac{2}{3} }\\\\E_{mid} = \frac{KQ}{(x^2 + r^2)^\frac{2}{3} }  - \frac{KQ}{(x^2 + r^2)^\frac{2}{3} } = 0

Therefore, the electric field strength at the mid-point between the two rings is zero.

7 0
3 years ago
Other questions:
  • How many states have 21 year old minimum drinking age laws
    5·1 answer
  • Why do FM stations drop out at shorter distances from their source than AM:?
    13·1 answer
  • 14. the sun's layer is called the photosphere . A. true . . b. false . . 15. meteoroids can form when comets break apart , creat
    12·1 answer
  • Circle the author's purpose for writing this passage
    8·2 answers
  • A fan rotating with an initial angular velocity of 1500 rev/min is switched off. In 2.5 seconds, the angular velocity decreases
    5·1 answer
  • Why is the heat of fusion of any substance generally lower than its heat of vaporization?
    9·1 answer
  • What is a proton?
    6·2 answers
  • What is the resultant of 5N force pointing north and 7N force pointing south? Do not forget include direction
    10·1 answer
  • A physicist wants to estimate the rate of emissions of alpha particles from a certain source. He counts 400 emissions in 80 seco
    12·1 answer
  • For a freely falling object dropped from rest, what is the acceleration at the
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!