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The work done onto the car is 506,250 J
The work done on a system implies an increase in the internal energy of the system as a result of some forces acting on the system from the outside.
From the parameters given:
- The mass of the car = 1500 kg
- The initial speed = 30 m/s
- The final speed = 15 m/s
The work done onto the car refers to the change in the kinetic energy (i.e. ΔK.E)



= 506,250 J
Therefore, we can conclude that the work done on the car is 506,250 J
Learn more about work done here:
brainly.com/question/18762601
Answer:
length of one side of the coil is 0.1083 m
Explanation:
given data
no of turn = 269
coil rotates = 113 rad/s
magnetic field = 0.222-T
peak output = 79.2 V
solution
we will apply here formula for maximum emf induced in a coil that is
εo = N × A × B × ω ........................1
and here Area A = l²
so
l =
put here value of A from equation 1
I =
put here value and we will get
l = 
l = 0.1083 m