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3 years ago

(Please help asap)

Physics

2 answers:

UNO [17]3 years ago

8 0

Answer:

mass yes

Explanation:

Bezzdna [24]3 years ago

3 0

Mass is usually defined in grams/kg

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In order for the ball to be able to make a complete circle around the peg, there must be sufficient speed at the top of its arc

Vesna [10]

Answer:

Explanation:

Let T be the tension in the swing

At top point $mg-T=\frac{mv^2}{r}$

where v=velocity needed to complete circular path

r=distance between point of rotation to the ball center=L+\frac{d}{2} (d=diameter of ball)

Th-resold velocity is given by $mg-0=\frac{mv^2}{r}$

To get the velocity at bottom conserve energy at Top and bottom

At top $E_T=mg\times 2L+\frac{mv^2}{2}$

Energy at Bottom $E_b=\frac{mv_0^2}{2}$

Comparing two as energy is conserved

$v_0^2=4gr+gr$

$v_0^2=5gr$

$v_0=\sqrt{5gr}$

$v_0=\sqrt{5g\left ( \frac{d}{2}+L\right )}$

6 0

3 years ago

A point charge gives rise to an electric field with magnitude 2 N/C at a distance of 4 m. If the distance is increased to 20 m,

worty [1.4K]

Answer:

0.08 N/C

Explanation:

Electric Field: This is defined as the force per unit charge exerted at a point. The expression for electric field is given as,

E = Kq/r².............................. Equation 1

Where E = Electric Field, q = Charge, k = proportionality constant, r = distance.

making q the subject of the equation,

q = Er²/k............................... Equation 2

Given: E = 2 N/C, r = 4 m,

Substitute into equation 2

q = 2(4)²/k

q = 32/k C.

When r is increased to 20 m,

E = k(32/k)/20²

E = 32/400

E = 0.08 N/C.

Hence the electric Field = 0.08 N/C

5 0

4 years ago

a standing wave in a pipe with both ends open has a frequency of 348. hz. the next higher harmonic has a frequency of 522. hz.

miskamm [114]

Answer:

A pipe open at both ends would have an antinode at each end and its length would be λ/ 2

The next such points would be λ and 3 λ / 2

The ratio of 522 / 348 is 1.5 so the harmonic at 348 is one wavelength and the next harmonic is 3 λ / 2 at 1 1/2 wavelengths

348 hz would occur at one wavelength

f λ = v = f L where the length of the pipe is one wavelength

if we use 331 as the speed of sound then

L = 331 / 348 = .95 m for the length of the pipe

8 0

2 years ago

4.5 cm3 of water is boiled at atmospheric pressure to become 4048.3 cm3 of steam, also at atmospheric pressure. Calculate the wo

Mrrafil [7]

1. 408.4 J

The work done by a gas is given by:

$W=p\Delta V$

where

p is the gas pressure

$\Delta V$ is the change in volume of the gas

In this problem,

$p=1.01\cdot 10^5 Pa$ (atmospheric pressure)

$\Delta V=4048.3 cm^3 - 4.5 cm^3 =4043.8 cm^3 = 4043.8 \cdot 10^{-6}m^3$ is the change in volume

So, the work done is

$W=(1.01\cdot 10^5 Pa)(4043.8 \cdot 10^{-6}m^3)=408.4 J$

2. 10170 J

The amount of heat added to the water to completely boil it is equal to the latent heat of vaporization:

$Q = m \lambda_v$

where

m is the mass of the water

$\lambda_v = 2.26\cdot 10^6 J/kg$ is the specific latent heat of vaporization

The initial volume of water is

$V_i = 4.5 cm^3 = 4.5\cdot 10^{-6}m^3$

and the water density is

$\rho = 1000 kg/m^3$

So the water mass is

$m=\rho V_i = (1000 kg/m^3)(4.5\cdot 10^{-6}m^3)=4.5\cdot 10^{-3}kg$

So, the amount of heat added to the water is

$Q=(4.5\cdot 10^{-3}kg)(2.26\cdot 10^6 J/kg)=10,170 J$

8 0

4 years ago

The light rays in the illustration below do not properly focus at the focal point. this problem occurs with?

tankabanditka [31]

Answer:

The problem occurs with all spherical mirrors.

Spherical mirrors are practical up to about inches in diameter.

Reflecting telescopes use spherical mirrors for apertures up to about 4 ".

Larger aperture telescopes use parabolic mirrors to obtain sharp focus.

7 0

3 years ago