Who was the last person to step on the moon?

Physics

2 answers:

Pavlova-9 [17]3 years ago

5 0

Eugene Cernan was not the last, but he was the most recent.

notsponge [240]3 years ago

5 0

The last person to walk on the moon was Apollo astronaut Eugene Cernan. <span />

You might be interested in

1 Do alien exist<br>2 why sky is blue<br>3 what is the weight of sky<br>4 why occasion is blue

snow_lady [41]

1. Yes it is most likely that aliens exist because we have a whole universe yet to discover and us humans can’t be the only species alive
2. Blue light travels faster than any other color in the color prism and is scattered throughout more in the sky than other colors
3.

3 0

3 years ago

Read 2 more answers

The drawing shows three particles far away from any other objects and located on a straight line. The masses of these particles

tamaranim1 [39]

Answer:

A: 5.67*10^-5 N

B: 3.49*10^-5 N

C: -9.16*10^-5 N

Explanation:

$\\A\\F_{A} = F_{BA} + F_{CA} =G*\frac{m_{b}*m_{a}}{r^2_{AB}} + G*\frac{m_{c}*m_{a}}{r^2_{AC}} \\\\= (6.67*10^(-11))*(\frac{363*517}{0.5^2} + \frac{154*363}{0.75^2})\\\\= 5.67*10^-5 N \\\\B\\\\F_{B} = -F_{BA} + F_{CB} =-G*\frac{m_{b}*m_{a}}{r^2_{AB}} + G*\frac{m_{c}*m_{b}}{r^2_{BC}} \\\\= (6.67*10^(-11))*(-\frac{517*363}{0.5^2} + \frac{517*154}{0.25^2})\\\\= 3.49*10^-5\\\\$

$F_{C} = -F_{CA} - F_{CB} =-G*\frac{m_{b}*m_{c}}{r^2_{BC}} - G*\frac{m_{c}*m_{a}}{r^2_{AC}} \\\\= (6.67*10^(-11))*(-\frac{517*154}{0.25^2} - \frac{154*363}{0.75^2})\\\\= -9.16*10^-5$