M*U + 0 = m*v'1 + 2m*v'2
the zero means deuteron has no velocity
<span>where v'1 and v'2 are the post-collision velocities.
</span>The equatio becomes
<span>U = v'1 + 2v'2</span>
<span>U = v'2- v'1 </span>
<span>v'2 = U + v'1 </span>
<span>U = v'1 + 2(U + v'1) = 2U + 3v'1 </span>
<span>U = -3V </span>
<span>V = -U / 3 </span>
<span>The speed ratio is 1/3 </span>
<span>B) Since KE is proportional to the square of the speed, if the speed is 1/3, then KE is 1/9 </span>
<span>C) (1/3)ⁿ = 1/729 </span>
<span>3ⁿ = 729 </span>
<span>n = 6 </span>
The correct answer is 223 days.
The relationship between the duration of revolution and the separation between the sun is shown by Kepler's third law. Using the notions of circular motion and the gravitational and centripetal forces, we may obtain this equation.
According to Kepler's third rule, the semi-major axis of an orbit is linked to the orbital period of a planet around the sun as follows:
p² = a³
where an is the semi-major axis/distance to the star and p is the orbital period in years.
It is said that a = 0.72 AU for Venus.
P= √(0.72 AU)^3 = 0.61 years.
365 days in a year = 222.9 ≈ 223 days.
To learn more about Kepler's third rule refer the link:
brainly.com/question/1608361
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Answer:
The are moving with a speed of 25 m/s after the collision.
Explanation:
assuming the mass (m) of the cars are equal, let v = 20 m/s be the velocity of the driver in the front and u = 30 m/s be the velocity of the driver behind. let V be the velocity of the cars after the collision.
then, by conservation of linear momentum:
m×(v + u) = V×2×m
(v + u) = V×2
V = (v + u)/2
= (20 + 30)/2
= 25 m/s
Therefore, the are moving with a speed of 25 m/s after the collision.
