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3 years ago

Given 1 inch ≡ 2.54 cm and 1 foot ≡

Physics

1 answer:

d1i1m1o1n [39]3 years ago

3 0

Answer:

2991.47 [cm^2]

Explanation:

To solve this problem we must perform a dimensional analysis and use the corresponding conversion values:

$3.22[ft^{2}]*\frac{12^{2}in^{2} }{1^{2}ft^{2}} *\frac{2.54^{2}cm^{2} }{1^{2}in^{2} } \\2991.47[cm^{2}]$

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What is the equation: If F=10 N, a=5 m/s², m=?

Romashka-Z-Leto [24]

Answer:

2 kg

Explanation:

Remember:

F = m * a re-arrange to

F/a = m substitute in the given values

10 / 5 = 2 kg

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2 years ago

The temperature of a room is 77°F what would be the temperature in Celsius scale

anygoal [31]

Formulas change from F to degree C : C = ( F - 32 )/1.8

so we have (77-32)/1.8 = 25 oC

ok done. Thank to me :>

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3 years ago

By what factors does the speed of the elctron exceed that of the proton?

____ [38]

Answer:

» An electron is lighter than a proton.

explanation:

${ = \: \sf{an \: electron \: has \: formula \: \: }}{ \bf{ {}^{0}_{ - 1}e }}$

hence it's mass number is zero

${ = \: \sf{an \: electron \: is \: helium \: particle \: \: }}{ \bf{ {}^{4} _{2}He }}$

hence it's mass number is 4

Therefore, proton is heavier than electron

» An electron has a small charge magnitude than a proton.

Explanation:

An electron has charge of -1 while proton has charge of +2, therefore electron is less deflected by any energetic fields than a proton

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3 years ago

A muon is a short-lived particle. It is found experimentally that muonsmoving at speed 0.9ccan travel about 1500 meters between

Monica [59]

Answer:

a) $t=5.5\mu s$

b) $\Delta t'=12.5\mu s$

Explanation:

a) Let's use the constant velocity equation:

$v=\frac{\Delta x}{\Delta t}$

v is the speed of the muon. 0.9*c
c is the speed of light 3*10⁸ m/s

$t=\frac{\Delta x}{v}=\frac{1500}{0.9*(3*10^{8})}$

$t=5.5\mu s$

b) Here we need to use Lorentz factor because the speed of the muon is relativistic. Hence the time in the rest frame is the product of the Lorentz factor times the time in the inertial frame.

$\Delta t'=\gamma\Delta t$

$\gamma =\frac{1}{\sqrt{1-\frac{v^{2}}{c^{2}}}}$

v is the speed of muon (0.9c)

Therefore the time in the rest frame will be:

$\Delta t'=\frac{1}{\sqrt{1-\frac{(0.9c)^{2}}{c^{2}}}}\Delta t$

$\Delta t'=\frac{1}{\sqrt{1-0.9^{2}}}\Delta t$

$\Delta t'=\frac{1}{0.44}\Delta t$

No we use the value of Δt calculated in a)

$\Delta t'=2.27*5.5=12.5\mu s$

I hope it helps you!

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4 years ago

Olaf takes a picture of his dog using a digital camera. Which is true regarding the image of the dog detected by sensors in the

trasher [3.6K]

Answer: a. forms where light rays coming from the dog converge.

Explanation:

While photographing through digital camera, the light from the object through the lens converges and falls on image sensor.

The image breaks into many pixels and color and brightness of each pixel is measured and stored in form of number. This forms a digital image.

Thus, the correct option is a because the lens converges the light coming from the object onto the sensor.

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3 years ago

Read 2 more answers