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hodyreva [135]
3 years ago
14

Given 1 inch ≡ 2.54 cm and 1 foot ≡

Physics
1 answer:
d1i1m1o1n [39]3 years ago
3 0

Answer:

2991.47 [cm^2]

Explanation:

To solve this problem we must perform a dimensional analysis and use the corresponding conversion values:

3.22[ft^{2}]*\frac{12^{2}in^{2} }{1^{2}ft^{2}} *\frac{2.54^{2}cm^{2}  }{1^{2}in^{2} } \\2991.47[cm^{2}]

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Consider a highway composed of concrete. If the road is 4.5 km long, 30 m wide, and 0.70 m thick, what is its mass?
Aloiza [94]

Answer:

Explanation:

We need to assume that the density of the concrete is about 2350 Kg/m^3. And using the dimensions of the highway we can calculate the volume of the highway.

vh=4500 * 30 * 0,70\\vh=94500 m^3\\den=m/v\\m=den*v\\m=2350*94500\\\\m=222075 ton

5 0
3 years ago
Un objeto se suelta desde determinada altura y emplea un tiempo t en caer al suelo. Si se cuadruplica la altura desde la cual se
blondinia [14]

When an object falls from a h height, you should work with the uniformly accelerated linear movement equations:

y=½*a*t²+Vo*t+yo

You should consider:

a=-g=-10m/s²

yo=h

If it’s a freefall, it means it starts from rest, which means it has no initial velocity:

Vo=0

Replacing that information in the equation:

y=½*(-10m/s²)*t²+0*t+h=-5m/s²*t²+0+h=-5m/s²*t²+h

So this is the

Besides, if you want to find out how long it takes for it to get to the floor, you should put the height of the floor as final height, which would be 0 (assuming the initial height has been measured from there):

y=0

0=-5m/s²*t²+h

5m/s²*t²=h

t²=h/(5m/s²)

t=√(h/(5m/s²))

t=√(hs²/(5m))

t=(√(h/(5m)))s

<span>If we <span>quadruple </span>h:</span>

t2=(√(h2/(5m)))s=(√(4*h1/(5m)))s=(√4)*(√h1/(5m)))s=2*(√h1/(5m)))s=2*t1

This 4 goes inside the square root, so then it converts to 2. So the new time is twice as much the previous time.

Concerning velocity, you have to use the other equation:

v=at+vo

As I said before, a is gravity and vo is zero.

v=-10m/s²*t+0=-10m/s²*t

Final velocity is directly related to time, so if time is doubled, so is velocity.

v2=-10m/s²*t2=-10m/s²*(2*t1)=2*(-10m/s²*t1)=2*v1

<span>So the correct answer is A, and the other ones are false.</span>

8 0
3 years ago
A rope breaks when the tension reaches 205 N. What is the maximum speed at which it can swing a 0.477 kg mass in a circle of rad
jekas [21]

Answer:

Maximum velocity will be 17.651 m /sec

Explanation:

We have given a rope breaks when tension reaches 205 N

Mass m = 0.477 kg

Radius of the circle r = 0.725 m

Tension in the rope is given by

T=\frac{mv^2}{r}

205=\frac{0.477\times v^2}{0.725}

0.477v^2=148.625

v^2=311.5828

v = 17.651 m /sec

8 0
3 years ago
a planes average speed between two cities is 600 km/hrs. if the trip takes 2.5 its how for does the plane fly
Nastasia [14]
It’s 600 x 2.5 which is 1500. So the plane flies about 1500km in 2.5 hrs.
4 0
3 years ago
Read 2 more answers
A redox reaction is always a single-displacement reaction, but a single-
Maurinko [17]
True, because it’s true
5 0
3 years ago
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