We can solve the problem by using the first law of thermodynamics:
where
is the change in internal energy of the system
is the heat absorbed by the system
is the work done by the system on the surrounding
In this problem, the work done by the system is
with a negative sign because the work is done by the surrounding on the system, while the heat absorbed is
with a negative sign as well because it is released by the system.
Therefore, by using the initial equation, we find
<span>gravitational force = 0.1 mg-wt. = 0.1 * 10^-6 * 9.8 N = Gm1m2/r^2
m1 = 40 kg m2 =15 kg and r = 0.2 m
Put in and find G</span>
Answer:
a) The charge of the capacitor is 4.25x10⁻¹¹C
b) The charge of the capacitor is 4.25x10⁻¹¹C because the battery is disconnected.
c) The potential difference across the plates is 18 V
d) The work is 7.64x10⁻¹⁰J
Explanation:
The capacitance of the capacitor is equal to:
A = 2 cm² = 0.0002 m²
d = 0.5 mm = 0.0005 m
Replacing:
a) The charge of the capacitor is equal to:
Q = C*V = 3.54 * 12 = 42.48 pC = 4.25x10⁻¹¹C
b) The charge is the same because the battery is disconnected (Q = 4.25x10⁻¹¹C)
c) If distance is increased, we have:
The potential is:
d) The work done is equal to:
The time taken for the spaceship to increase its speed from 11.1 km/s to 11.7 km/s is 107 s
<h3>Data obtained from the question</h3>
The following data were obtained from the question given above:
- Initial velocity (u) = 11.1 Km/s
- Final velocity (v) = 11.7 Km/s
- Distance (s) = 1220 Km
- Time (t) =?
<h3>How to determine the time</h3>
The time taken for the spaceship to increase its speed from 11.1 km/s to 11.7 km/s can be obtained as illustrated below:
s = (u + v)t / 2
Cross multiply
(u + v)t = 2s
Divide both sides by (u + v)
t = 2s / (u + v)t
t = (2 × 1220) / (11.1 + 11.7)
t = 2440 / 22.8
t = 107 s
Thus, the time taken for the spaceship to change its speed is 107 s
Learn more about speed:
brainly.com/question/680492
Learn more about velocity:
brainly.com/question/3411682
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