Answer:
there is no "following". if you can attach an image for me, ill be glad to help.
Explanation:
have a good day,
~evita
Answer:
![[NH_2NO_2]=0.0868M](https://tex.z-dn.net/?f=%5BNH_2NO_2%5D%3D0.0868M)
Explanation:
Hello,
In this case, for the given chemical reaction, the first-order rate law is:
![r=\frac{d[NH_2NO_2]}{dt} =-k[NH_2NO_2]](https://tex.z-dn.net/?f=r%3D%5Cfrac%7Bd%5BNH_2NO_2%5D%7D%7Bdt%7D%20%3D-k%5BNH_2NO_2%5D)
Which integrated is:
![[NH_2NO_2]=[NH_2NO_2]_0exp(-kt)](https://tex.z-dn.net/?f=%5BNH_2NO_2%5D%3D%5BNH_2NO_2%5D_0exp%28-kt%29)
Thus, the concentration after 31642.0 s for a 0.384-M solution is:
![[NH_2NO_2]=0.384M*exp(-4.70x10^{-5}s^{-1}*31642.0s)\\](https://tex.z-dn.net/?f=%5BNH_2NO_2%5D%3D0.384M%2Aexp%28-4.70x10%5E%7B-5%7Ds%5E%7B-1%7D%2A31642.0s%29%5C%5C)
![[NH_2NO_2]=0.0868M](https://tex.z-dn.net/?f=%5BNH_2NO_2%5D%3D0.0868M)
Best regards.
Answer:
17.2mL are needed
Explanation:
<em>The pH curve for titration of 50.0 mL of a 0.100 M solution of hydrochloric acid</em>
<em />
A strong acid as HCl reacts with a strong base as NaOH producing water and a salt. The chemical equation is:
HCl + NaOH → H₂O + NaCl
<em>Where 1 mole of HCl reacts per mole of NaOH</em>
<em />
To solve this question we must find the moles of HCl added = Moles NaOH you must add to reach the equivalence point. With these moles and the molar concentration we can find the volume that would be needed as follows:
<em>Moles HCl:</em>
50.0mL = 0.0500L * (0.100moles / L) = 0.00500 moles HCl = Moles NaOH
<em>Volume NaOH:</em>
0.00500 moles NaOH * (1L / 0.290moles) = 0.0172L NaOH =
<h3>17.2mL are needed</h3>
Answer:
uhhh im not a boy ima just answer this for points
Explanation:
:))))
Hey, its alright bro! I gotchu.
Im pretty sure the galactic symbol is the same reference to the symbol of the element on the periodic table.
For an example (Hydrogen) is H
So if im correct im pretty sure its referring to the symbols for each element
Hopefully this helps