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Kamila [148]
3 years ago
11

An independent variable is

Chemistry
1 answer:
Vsevolod [243]3 years ago
6 0

Answer:

C

Explanation:

a variable does that dose not depend on that of another

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A sample of neon gas occupies 4.5 L of gas at 1.63 atm. What will be the volume if the pressure changes to 2.4 atm
Alenkasestr [34]

Answer:

\boxed {\boxed {\sf 3.1 \ liters}}

Explanation:

This question asks us to find the new volume if the pressure changes. Therefore, we use Boyle's Law, which states that pressure and the volume of the gas are inversely proportional. The formula is:

P_1V_1=P_2V_2

We know that the original sample of gas occupies 4.5 liters at a pressure of 1.63 atmospheres.  We know that the pressure was changed to 2.4 atmospheres, but we don't know the volume. Substitute all known values into the formula.

4.5 \ L * 1.63 \ atm= 2.4 \ atm * V_2

Since we are solving for the new volume (V₂), we need to isolate the variable. It is being multiplied by 2.4 atmospheres and the inverse of multiplication is division. Divide both sides by 2.4 atm.

\frac {4.5 \ L * 1.63 \ atm}{2.4 \ atm}= \frac{2.4 \ atm * V_2}{2.4 \ atm}

\frac {4.5 \ L * 1.63 \ atm}{2.4 \ atm}= V_2

The units of atmospheres (atm) cancel.

\frac {4.5 \ L * 1.63 }{2.4 }=V_2

\frac {7.335 \ L}{2.4 }=V_2

3.05625 \ L= V_2

The smallest number of significant figures in the original measurements is 2, so our answer must have the same. For the number we found, that is the tenths place.

The 5 in the hundredth place tells us to round the 0 up to a 1.

3.1 \ L = V_2

The volume of the neon gas when the pressure is changed to 2.4 atmospheres is <u>3.1 Liters.</u>

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How many atoms of chlorine are there in 16.5 g of iron (iii) chloride?
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Fecl3 has a RFM of 56 + (35.5 * 3) = 162.5

so find out its moles 16.5 ÷ 162 5 = aprox. 0.1M

then there is a 1 : 3 ratio so 0.1 * 3 = 0.3

then times that by the avogado constant which is 6.02×10^23

0.3 × 6.02×10^23 = ans

hope that helps
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