Answer:
C. 0.2 Hertz
Explanation:
The frequency of a spring is equal to the reciprocal of the period:
where
f is the frequency
T is the period
For the spring in this problem,
T = 5 s
therefore, the frequency is
The speed of a car increases uniformly from 6 m/s to 42 m/s in 9 second calculate the acceleration of the car
1 answer:
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Answer:
0.176m from the flagpole, westward.
Explanation:
Let the Eastward be the positive direction. So initially runner A is at position -6km, running with velocity of 9km/h while runner B is at position 5km running at a velocity of -8km/h. We can conduct the following equation for their distances over the same time t
When A an B meets, they are at the same position and at the same time. So
So where they meet is 0.176m from the flagpole, westward.