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DochEvi [55]
2 years ago
15

The speed of a car increases uniformly from 6 m/s to 42 m/s in 9 second calculate the acceleration of the car​

Physics
1 answer:
djyliett [7]2 years ago
5 0

The acceleration of the car​ which changes the speed uniformly is 4 m/s²

<h3>What is acceleration?</h3>

Acceleration can be defined as the rate change of velocity with time.

acceleration a = (Δv) / (Δt)

Given is the initial velocity 6m/s and final velocity 42m/s, the time take fir this change in speed is 9s.

Substitute the values, we have

a = (42-6)/9

a = 36/9

a =4 m/s²

Thus, the acceleration is 4 m/s²

Learn more about acceleration.

brainly.com/question/12550364

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Answer:

In a unit government, all the powers of government are moved around in the central government where in turn in a federal government, the powers of government are divided between the center and the units.

Explanation:

I hope this helps.

5 0
1 year ago
What is the gravitational potential energy of a 3 kg ball kicked into the air at a height of 5 meters?
sladkih [1.3K]

formula for gravitational P.E =mgh

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3 years ago
An electric heater is rated 1000watts. If a current of 5A pass through the heater, find the value of its resistance.​
ICE Princess25 [194]

Answer: R=40 Ω

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3 years ago
Which of these is an experiment generally regarded as being first carried out by James Joule?
Sholpan [36]
1. The correct answer among the choices provided is the third option. Measuring the temperature increase of water from doing work by stirring it is an experiment generally regarded as being first carried out by James Joule.
2.  Joule's experiment directly shows that heat is a form of energy. He wanted to make a different way of measuring energy.
8 0
3 years ago
Read 2 more answers
A 0.600 kg block is attached to a spring with spring constant 15 N/m. While the block is sitting at rest, a student hits it with
gulaghasi [49]

Answer:

8.8 cm

31.422 cm/s

Explanation:

m = Mass of block = 0.6 kg

k = Spring constant = 15 N/m

x = Compression of spring

v = Velocity of block

A = Amplitude

As the energy of the system is conserved we have

\dfrac{1}{2}mv^2=\dfrac{1}{2}kA^2\\\Rightarrow A=\sqrt{\dfrac{mv^2}{k}}\\\Rightarrow A=\sqrt{\dfrac{0.6\times 0.44^2}{15}}\\\Rightarrow A=0.088\ m\\\Rightarrow A=8.8\ cm

Amplitude of the oscillations is 8.8 cm

At x = 0.7 A

Again, as the energy of the system is conserved we have

\dfrac{1}{2}kA^2=\dfrac{1}{2}mv^2+\dfrac{1}{2}kx^2\\\Rightarrow v=\sqrt{\dfrac{k(A^2-x^2)}{m}}\\\Rightarrow v=\sqrt{\dfrac{15(0.088^2-(0.7\times 0.088)^2)}{0.6}}\\\Rightarrow v=0.31422\ m/s

The block's speed is 31.422 cm/s

4 0
3 years ago
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