The efficiency of an ideal Carnot heat engine can be written as:

where

is the temperature of the cold region

is the temperature of the hot region
For the engine in our problem, we have

and

, so the efficiency is
Answer:
The depth of the water at this point is 0.938 m.
Explanation:
Given that,
At one point
Wide= 16.0 m
Deep = 3.8 m
Water flow = 2.8 cm/s
At a second point downstream
Width of canal = 16.5 m
Water flow = 11.0 cm/s
We need to calculate the depth
Using Bernoulli theorem

Put the value into the formula



Hence, The depth of the water at this point is 0.938 m.
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Answer:
(B) at the middle of the pipe
Explanation:
In the case of an open pipe which vibrates in fundamental mode, an anti-node is formed at the middle of the pipe, here the amplitude of the wave is maximum. Hence, the pressure variation is also maximum at the middle.
Answer:
F
Explanation:
When comparing two vector quantities you have to compare both magnitude and direction,but for scalar you only compare magnitude