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pochemuha
3 years ago
13

Suppose it takes 1.4 s for the monkey to catch the coconut and the initial upward speed of the coconut is 2.9 m/s. Assume the ac

celeration of gravity is 9.8 m/s 2 . Determine the y coordinate of the location where the monkey catches the coconut. Answer in units of m.
Physics
1 answer:
AVprozaik [17]3 years ago
8 0

Answer:

y-coordinate where the monkey catches the coconut is 13.664 m.

Explanation:

Given;

time taken for the monkey to catch the coconut, t = 1.4 s

initial upward speed of the coconut, Uy = 2.9 m/s

acceleration due to gravity, g = 9.8 m/s²

The y-coordinate where the monkey catches the coconut is calculated as;

h_y = U_yt +\frac{1}{2} gt^2\\\\h_y = (2.9\times 1.4) +\frac{1}{2} (9.8)(1.4^2)\\\\h_y = 4.06 + 9.604\\\\h_y = 13.664 \ m

Therefore, y-coordinate where the monkey catches the coconut is 13.664 m.

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<em>"A concave lens is thinner at the center than it is at the edges."</em>

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Dominic made the table below to organize his notes about mixtures.
Andrei [34K]

Answer:

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A tray of electronic components contains 15 components, 4 of which are defective. If 4 components are selected, what is the poss
dlinn [17]

Answer:

a) 0.0007326

b) 0.03223

c) 0.2418

d) 0.2418

Explanation:

To find different probabilities for the selection of components among eleven good and four defective components, we will use the Combination.

a) C(4,4) = 1; C(15,4) = 1365

P = \frac{C(4,4)}{C(15,4)} = \frac{1}{1365} = 0.0007326

b) C(4,3) = 4; C(11,1) = 11

P = \frac{C(4,3)*C(11,1)}{C(15,4)} = \frac{4*11}{1365} = 0.03223

c) C(4,2) = 6; C(11,2) = 55

P = \frac{C(4,2)*C(11,2)}{C(15,4)} = \frac{6*55}{1365} = 0.2418

d) C(11,4) = 330

P = \frac{C(11,4)}{C(15,4)} = \frac{330}{1365} = 0.2418

8 0
3 years ago
Nuclear _________ reactions convert protons into helium; thus, becoming the source of all energy radiated by the sun. A) fission
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Nuclear fusion reactions convert protons into helium; thus, becoming the source of all energy radiated by the sun.

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3 0
3 years ago
A person hits a tennis ball with a mass of 0.058 kg against a wall.
horrorfan [7]

Explanation:

Mass of the ball, m = 0.058 kg

Initial speed of the ball, u = 11 m/s

Final speed of the ball, v = -11 m/s (negative as it rebounds)

Time, t = 2.1 s

(a) Let F is the average force exerted on the wall. It is given by :

F=\dfrac{m(v-u)}{t}

F=\dfrac{0.058\times (11-(-11))}{2.1}

F = 0.607 N

(b) Area of wall, A=3\ m^2

Let P is the average pressure on that area. It is given by :

P=\dfrac{F}{A}

P=\dfrac{0.607\ N}{3\ m^2}

P = 0.202 Pa

Hence, this is the required solution.

8 0
3 years ago
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