1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vilka [71]
3 years ago
8

A 5000-kg spacecraft is in a circular orbit 2000 km above the surface of mars. how much work must the spacecraft engines perform

to move the spacecraft to a circular orbit that is 4000 km above the surface?
Physics
1 answer:
Elden [556K]3 years ago
8 0
The spacecraft is orbiting at 2000 Km. The engine has to put it on 4000 km altitude, therefore the engine has to push it into another 2000 km, so that it will attain the 4000 km altitude.

Given. Gravitational pull of planet Mars g = 3.71 m/s²

            Mass of the spacecraft m = 5000 kg

Formula: W = fd   F = mg    

               W = mgh

               W = (5000 Kg)(3. 71 m/s²)(2 x 10⁶m)

               W = 3.71 x 10¹⁰ J

             
You might be interested in
The horizontal beam in Fig. E11.14 weighs 190 N, and its center of gravity is at its center. Find (a) the tension in the cable a
grandymaker [24]

Answer:

(a). The tension in the cable is 658.33 N.

(b). The horizontal components of the force exerted on the beam at the wall is 526.66 N.

(c). The vertical components of the force exerted on the beam at the wall is 95.002 N.

Explanation:

Given that,

Weight of beam= 190 N

Here, The center of gravity is at its center

According to figure,

The angle is

\sin\theta=\dfrac{3}{5}

The horizontal component is

T_{x}=T\cos\theta

The vertical component is

T_{y}=T\sin\theta

(a). We need to calculate the tension in the cable

Using formula of net torque acting on the pivot

\sum\tau=F_{b}\times r+F_{w}\times r'-T\sin \theta\times r'

Put the value into the formula

0=190\times2+300\times 4-T\sin\theta\times 4

T\sin\theta\times 4=380+1200

T=\dfrac{1580\times5}{3\times 4}

T=658.33\ N

(b). We need to calculate the horizontal components of the force exerted on the beam at the wall

Using formula of horizontal component

F_{x}=T\cos\theta

Put the value into the formula

F_{x}=658.33\times\dfrac{4}{5}

F_{x}=526.66\ N

(c). We need to calculate the vertical components of the force exerted on the beam at the wall

Using formula of vertical component

F_{y}=F_{b}+F_{w}-T\sin\theta

Put the value into the formula

F_{y}=190+300-658.33\times\dfrac{3}{5}

F_{y}=95.002\ N

Hence, (a). The tension in the cable is 658.33 N.

(b). The horizontal components of the force exerted on the beam at the wall is 526.66 N.

(c). The vertical components of the force exerted on the beam at the wall is 95.002 N.

3 0
3 years ago
An electric generator converts kinetic energy into --------<br> energy.
pickupchik [31]

The correct answer to the question is :  Electric energy

EXPLANATION :

As per the question, we have an electric generator.

Before coming into any conclusion, first we have to understand the function of generator.

The generator is attached to the turbine. When the turbine rotates, the generator also starts rotating with it. Thanks to electromagnetic induction, the electricity is produced in the coil attached to the generator when it rotates.

Hence, from above, it is obvious that kinetic energy is converted into electric energy.

3 0
3 years ago
Read 2 more answers
A body falls from the top of the tower and during the last second of its fall it fall through 23mvfind height of tower.
DanielleElmas [232]

Answer:

39.7 m

Explanation:

First, we conside only the last second of fall of the body. We can apply the following suvat equation:

s=ut+\frac{1}{2}at^2

where, taking downward as positive direction:

s = 23 m is the displacement of the body

t = 1 s is the time interval considered

a=g=9.8 m/s^2 is the acceleration

u is the velocity of the body at the beginning of that second

Solving for u, we find:

ut=s-\frac{1}{2}at^2\\u=\frac{s}{t}-\frac{1}{2}at=\frac{23}{1}-\frac{1}{2}(9.8)(1)=18.1 m/s

Now we can call this velocity that we found v,

v = 18 m/s

And we can now consider the first part of the fall, where we can apply the following suvat equation:

v^2-u^2 = 2as'

where

v = 18 m/s

u = 0 (the body falls from rest)

s' is the displacement of the body before the last second

Solving for s',

s'=\frac{v^2-u^2}{2a}=\frac{18.1^2-0}{2(9.8)}=16.7 m

Therefore, the total heigth of the building is the sum of s and s':

h = s + s' = 23 m + 16.7 m = 39.7 m

7 0
3 years ago
A footballer kicks a ball at an angle of 45° with the horizontal. If the ball was in the air
Naily [24]

Answer:

HOPE THIS ANSWER WILL HELP YOU

3 0
3 years ago
3. Jeremy has a solution with a mass of 228 g. He knows that the mass of the solvent was 224 g. How much is the mass of the solu
mariarad [96]
228 - 224 = 4

there is 4g of solute in the solution.
3 0
2 years ago
Other questions:
  • What role does density play in the movement of convection curruents?
    5·1 answer
  • Which path would light follow as it travels through glass?
    5·2 answers
  • A telescope can be used to enlarge the diameter of a laser beam and limit diffraction spreading. The laser beam is sent through
    5·1 answer
  • In a local bar, a customer slides an empty beer mug down the counter for a refill. The height of the counter is 1.2 m. The mug s
    13·1 answer
  • The following are ways to properly manage your stress except
    6·1 answer
  • QUESTION 2 DOK 3 A Thompson's gazelle has a maximum acceleration of 4.5 m/s2 At this acceleration, how much time is required for
    10·1 answer
  • Describe how wavelength is defined for transverse waves and for longitudinal waves.
    10·1 answer
  • ¿Una bombilla de 50 vatios transfiere mas energía por unidad de tiempo que una bombilla de 100 vatios?
    12·1 answer
  • Why we don’t feel atmospheric pressure?
    15·2 answers
  • A girl pushes her little brother on his sled with a force of 300 N for 750 m.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!