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OverLord2011 [107]
3 years ago
5

A block of ice is cooled from -0.5 degrees Celsius to -10.1 degrees Celsius. Calculate the temperature change, delta T, in degre

es Celsius and in kelvins.
Chemistry
1 answer:
ss7ja [257]3 years ago
3 0
Delta T= T final - T initial
Tfinal= -101.1 °C
Tinitial= -0.5 °C
•Delta T = -101.1°C - (-0.5°C)
=100.6°C

Kelvin= °C + 273
= -100.6 + 273
= 172.4 Kelvin
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The process involved in this problem are :

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Q=[m\times c_{p,l}\times (T_{final}-T_{initial})]+[m\times \Delta H_{fusion}]+[m\times c_{p,s}\times (T_{final}-T_{initial})]

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Now put all the given values in the above expression, we get:

Q=[94.4g\times 1.73J/g.K\times (279-322)K]+[94.4g\times -125.6J/g]+[94.4g\times 1.51J/g.K\times (205-279)K]

Q=-29427.312J=-29.4kJ

Negative sign indicates that the heat is removed from the system.

Therefore, the energy removed must be, 29.4 kJ

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