Ask question

Ask question

All categories

3 years ago

15

Visible light is a range of _____ energy EM waves in the electromagnetic spectrum that the human eye can see. A. zero B. high C.

low D. medium

2 answers:

patriot [66]3 years ago

7 0

The answer is a or d

vfiekz [6]3 years ago

4 0

The visible light falls into the measure of low energy range in the electromagnetic spectrum.

Answer: Option C

<u>Explanation:</u>

The visible light is one of the 7 kind of electromagnetic spectrum that we know. Of those 7 kind, the visible light falls in between of the electromagnetic spectrum according to the wavelength of the light.

The visible light consists of VIBGYOR where the red has the 1.8 eV of the energy with violet to have around 3.4 eV. Therefore the correct answer is low.

You might be interested in

A wheel starts from rest and rotates with constant angular acceleration to reach an angular speed of 11.2 rad/s in 3.07 s. (a) f

Hitman42 [59]

(a) The angular acceleration of the wheel is given by
$\alpha = \frac{\omega_f - \omega_i }{t}$
where $\omega_i$ and $\omega_f$ are the initial and final angular speed of the wheel, and t the time.

In our problem, the initial angular speed is zero (the wheel starts from rest), so the angular acceleration is
$\alpha = \frac{(11.2 rad/s) - 0}{3.07 s} =3.65 rad/s^2$

(b) The wheel is moving by uniformly rotational accelerated motion, so the angle it covered after a time t is given by
$\theta (t) = \omega_i t + \frac{1}{2} \alpha t^2$
where $\omega_i = 0$ is the initial angular speed. So, the angle covered after a time t=3.07 s is
$\theta= \frac{1}{2} \alpha t^2 = \frac{1}{2}(3.65 rad/s^2)(3.07 s)^2 = 17.2 rad$

6 0

3 years ago

Which of the following does not illustrate a complete circuit?

Yakvenalex [24]

Answer:

I think A

Explanation:

because it dosn't have enough tools

4 0

2 years ago

A piano wire with mass 2.95 g and length 79.0 cm is stretched with a tension of 29.0 N . A wave with frequency 105 Hz and amplit

Romashka-Z-Leto [24]

The concept needed to solve this problem is average power dissipated by a wave on a string. This expression ca be defined as

$P = \frac{1}{2} \mu \omega^2 A^2 v$

Here,

$\mu$ = Linear mass density of the string

$\omega =$ Angular frequency of the wave on the string

A = Amplitude of the wave

v = Speed of the wave

At the same time each of this terms have its own definition, i.e,

$v = \sqrt{\frac{T}{\mu}} \rightarrow$ Here T is the Period

For the linear mass density we have that

$\mu = \frac{m}{l}$

And the angular frequency can be written as

$\omega = 2\pi f$

Replacing this terms and the first equation we have that

$P = \frac{1}{2} (\frac{m}{l})(2\pi f)^2 A^2(\sqrt{\frac{T}{\mu}})$

$P = \frac{1}{2} (\frac{m}{l})(2\pi f)^2 A^2 (\sqrt{\frac{T}{m/l}})$

$P = 2\pi^2 f^2A^2(\sqrt{T(m/l)})$

PART A ) Replacing our values here we have that

$P = 2\pi^2 (105)^2(1.8*10^{-3})^2(\sqrt{(29.0)(2.95*10^{-3}/0.79)})$

$P = 0.2320W$

PART B) The new amplitude A' that is half ot the wavelength of the wave is

$A' = \frac{1.8*10^{-3}}{2}$

$A' = 0.9*10^{-3}$

Replacing at the equation of power we have that

$P = 2\pi^2 (105)^2(0.9*10^{-3})^2(\sqrt{(29.0)(2.95*10^{-3}/0.79)})$

$P = 0.058W$

8 0

2 years ago

What could you add to a closed circuit consisting of 2 batteries, 2 light bulbs, and a switch to Increase the current?

Brilliant_brown [7]

Answer:

The following that could be used to make the simplest circuit are a battery, wire, switch, and a light bulb. The answer is letter D. The battery provides the energy for the bulb to work. The wire provides a pathway for the electrons to move. The switch provides the open and close of the circuit.

Explanation:

Hopefully this helped, if not HMU and I will get u a better answer

-Have a great day! :)

4 0

3 years ago

HELPPP PLEASEEEE, BRAINLEST WILL BE GIVEN

Alex17521 [72]

Answer:

nice question but I don't know please forgive me

5 0

3 years ago

Read 2 more answers