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mixer [17]
3 years ago
14

The enthalpy of solution (dissolving) of sodium hydroxide is given below. Determine the change in temperature of a coffee cup ca

lorimeter containing 150 ml of water when 5.00 g NaOH (40.00 g/mol) is added to the container. You may assume that the solution has the same specific heat and density as water.
NaOH(s) → NaOH(aq) ΔH =-44.51 KJ

a. +8.87°C

b. +2.70 C

c. 2.70°C

d. 8.87°C
Chemistry
1 answer:
geniusboy [140]3 years ago
7 0

Answer:

The change in temperature of a coffee cup calorimeter is 8.87°C.

Explanation:

Volume of the water = V = 150 g

Density of the water , d =1.0 g/mL

Mass of the water = M

M=d\times V=1.00 g/mL\times 150 ml =150.0 g

Mass of solution = m = M = 150.0 g

NaOH(s)\rightarrow NaOH(aq),\Delta H =-44.51 kJ/mol

Moles of NaOH = \frac{5.00 g}{40 g/mol}=0.125 mol

Energy released when 0.125 moles of NaOH added in water = Q

Q=0.125 moles\times (-44.51 kJ/mol)=-5.5638 kJ=-5,563.8 J

1 kJ = 1000 J

Heat gained by water = Q' = -Q ( conservation of energy)

Q'= 5,563.8 J

Specific heat of solution = c = 4.184 J/g°C

Change in temperature of the solution = \Delta T

Q'=mc\times \Delta T

5,563.8 J=150.0 g\times 4.184 J/g^oC\times \Delta T

\Delta T=\frac{5,563.8 J}{150.0 g\times 4.184 J/g^oC}=8.87^oC

The change in temperature of a coffee cup calorimeter is 8.87°C.

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