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dmitriy555 [2]
2 years ago
13

Write the word and balanced chemical equations for the reaction between:

Chemistry
1 answer:
Greeley [361]2 years ago
5 0

Answer:

HCl + Ca(OH)2 = CaCl2 + H2O - Chemical Equation Balancer.

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Calculate the molar mass of H2SO4 + 2 NaOH = Na2SO4 + 2 H2O. Please show all work. THANK YOU!
mr_godi [17]

Answer:

<em><u>30.11x1</u></em><em><u>0</u></em><em><u>²</u></em><em><u>³</u></em>

Explanation;

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7 0
2 years ago
The chemical formula for lithium phosphide is li3p
Oxana [17]
Sodium phosphide is the inorganic compound with the formula Na3P.
4 0
3 years ago
At a certain temperature the equilibrium constant, Kc, equals 0.11 for the reaction:
Butoxors [25]

<u>Answer:</u> The equilibrium concentration of ICl is 0.27 M

<u>Explanation:</u>

We are given:

Initial moles of iodine gas = 0.45 moles

Initial moles of chlorine gas = 0.45 moles

Volume of the flask = 2.0 L

The molarity is calculated by using the equation:

\text{Molarity}=\frac{\text{Number of moles}}{\text{Volume}}

Initial concentration of iodine gas = \frac{0.45}{2}=0.225M

Initial concentration of chlorine gas = \frac{0.45}{2}=0.225M

For the given chemical equation:

2ICl(g)\rightarrow I_2(g)+Cl_2(g);K_c=0.11

As, the initial moles of iodine and chlorine are given. So, the reaction will proceed backwards.

The chemical equation becomes:

                      I_2(g)+Cl_2(g)\rightarrow 2ICl(g);K_c=\frac{1}{0.11}=9.091

<u>Initial:</u>         0.225      0.225

<u>At eqllm:</u>   0.225-x    0.225-x     2x

The expression of K_c for above equation follows:

K_c=\frac{[ICl]^2}{[Cl_2][I_2]}

Putting values in above equation, we get:

9.091=\frac{(2x)^2}{(0.225-x)\times (0.225-x)}\\\\x=0.135,0.668

Neglecting the value of x = 0.668 because equilibrium concentration cannot be greater than the initial concentration

So, equilibrium concentration of ICl = 2x = (2 × 0.135) = 0.27 M

Hence, the equilibrium concentration of ICl is 0.27 M

6 0
3 years ago
Diana raises a 1000. N piano a distance of 5.00 m using a set of pulleys. She pulls
Alina [70]

Answer:

a) 250 N

b) 50 N

c) 5000 J

d) 4

e) 3.33

Explanation:

Given that weight of piano (F_r) = 1000 N, distance moved by pulley (d_r) = 5 m and the rope used (d_e) =20 m

a) The effort applied (F_e) if it was an ideal machine is:

F_e=\frac{F_rd_r}{d_e} = \frac{1000*5}{20}=250N

b) If the actual effort  = 300 N

The force to overcome friction = actual effort - F_e = 300 - 250 = 50 N

c) Work output = F_rd_r=1000*5=5000J

d) ideal mechanical  advantage (IMA) = \frac{d_e}{d_r} =\frac{20}{5} = 4

e) Input force = 300 N, Therefore:

actual mechanical advantage = F_r / input force = 1000 / 300 = 3.33

5 0
3 years ago
Solution A is 100 times as acidic as solution B. What is the difference in pH values of solution A and solution B
devlian [24]

Answer:

The difference is 2 pH units.

Explanation:

Let's give an arbitrary value to the H⁺ concentration of solution A, [H⁺]ₐ:

  • [H⁺]ₐ = 0.001 M

If that's the case then the pH of solution A would be:

  • pHₐ = -log(0.001) = 3

----

The H⁺ concentration of solution B ( [H⁺]ₓ ) is 100 higher than that, so:

  • [H⁺]ₓ = 0.001 * 100 = 0.1 M

And its pH:

  • pHₓ = -log(0.1) = 1

So the difference in pH values is:

  • pHₐ - pHₓ = 3 - 1 = 2
3 0
3 years ago
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