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3 years ago

Why must you be cautious of chemical exposure in the workplace?

Chemistry

1 answer:

Sholpan [36]3 years ago

5 0

Answer:

We must be cautious in chemical workspaces.

Explanation:

Chemistry laboratory or any chemical workspace contains many hazardous, poisonous chemicals or many hazardous chemicals may be produced during the chemical reactions. Smelling them or falling of chemicals on the body may cause many respiratory problems ,skin problems,nausea and many other side effects.They may also damage our eyes.Many chemicals are also flammable and may cause burns on our body.So we must be cautious of chemical exposure in the workspace.

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What is the total energy change for the following reaction:CO+H2O-CO2+H2

Alekssandra [29.7K]

Answer:

$\large \boxed{\text{-41.2 kJ/mol}}$

Explanation:

Balanced equation: CO(g) + H₂O(g) ⟶ CO₂(g) + H₂(g)

We can calculate the enthalpy change of a reaction by using the enthalpies of formation of reactants and products

$\Delta_{\text{rxn}}H^{\circ} = \sum \left( \Delta_{\text{f}} H^{\circ} \text{products}\right) - \sum \left (\Delta_{\text{f}}H^{\circ} \text{reactants} \right)$

(a) Enthalpies of formation of reactants and products

$\begin{array}{cc}\textbf{Substance} & \textbf{$\Delta_{\text{f}}$H/(kJ/mol}) \\\text{CO(g)} & -110.5 \\\text{H$_{2}$O} & -241.8\\\text{CO$_{2}$(g)} & -393.5 \\\text{H$_{2}$(g)} & 0 \\\end{array}$

(b) Total enthalpies of reactants and products

$\begin{array}{ccr}\textbf{Substance} & \textbf{Contribution)/(kJ/mol})&\textbf{Sum} \\\text{CO(g)} & -110.5& -110.5 \\\text{H$_{2}$O(g)} &-241.8& -241.8\\\textbf{Total}&\textbf{for reactants} &\mathbf{ -352.3}\\&&\\\text{CO}_{2}(g) & -393.5&-393.5 \\\text{H}_{2} & 0 & 0\\\textbf{Total}&\textbf{for products} & \mathbf{-393.5}\end{array}$

(c) Enthalpy of reaction $\Delta_{\text{rxn}}H^{\circ} = \sum \left( \Delta_{\text{f}} H^{\circ} \text{products}\right) - \sum \left (\Delta_{\text{f}}H^{\circ} \text{reactants} \right)= \text{-393.5 kJ/mol - (-352.3 kJ/mol}\\= \text{-393.5 kJ/mol + 352.3 kJ/mol} = \textbf{-41.2 kJ/mol}\\ \text{The total enthalpy change is $\large \boxed{\textbf{-41.2 kJ/mol}}$}$

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2 years ago

For a particular chemical reaction, the enthalpy of the reactants is -400 kJ. The enthalpy of the products is -390 kJ. The entro

Hunter-Best [27]

Answer:

For a particular chemical reaction, the enthalpy of the reactants is -400 kJ. The enthalpy of the products is -390 kJ. The entropy of the reactants is 0.2 kJ/K. The entropy of the products is 0.3 kJ/K. The temperature of the reaction is 25oC. What can you conclude about this reaction?

It is exergonic

It is endergonic

it is a redox reaction

It is being catalyzed by an enzyme

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2 years ago

In the process of eukaryotic pre-mRNA splicing, how is the lariat intermediate formed?

Aleks [24]

Answer:

Explanation:

The Eukaryotic pre-mRNA receives a 5' cap and 3'poly(A) tail before Introns are removed and the mRNA is considered ready for translation.

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2 years ago

Question 4 options: what is the volume of 1.2 moles of water vapor at stp?

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What is the volume of 1.2 moles of water vapor at STP?
The answer is 26.9

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3 years ago

Explain what an acid,a base and an alkali are.

BigorU [14]

Those are types of water on a pH scale 7.0 and above are alkili water and anything under that is acidic

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2 years ago

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