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USPshnik [31]
3 years ago
9

Why must you be cautious of chemical exposure in the workplace?

Chemistry
1 answer:
Sholpan [36]3 years ago
5 0

Answer:

We must be cautious in chemical workspaces.

Explanation:

Chemistry laboratory or any chemical workspace contains many hazardous, poisonous chemicals or many hazardous chemicals may be produced during the chemical reactions. Smelling them or falling of chemicals on the body may cause many respiratory problems ,skin problems,nausea and many other side effects.They may also damage our eyes.Many chemicals are also flammable and may cause burns on our body.So we must be cautious of chemical exposure in the workspace.

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I need help with chemical formulas<br>​
pochemuha

Answer:

Which one?

Explanation:

7 0
2 years ago
Help please
ss7ja [257]
0.0821 L-atm/mol-K
8.314 kPa-L/mol-K
7 0
2 years ago
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there are 3 isotopes of the element Gz: Gz-80,Gz-81,Gz-83. the average atomic mass of Gz is 82.74. what is the most abundant iso
Romashka-Z-Leto [24]

The most abundant isotope is Gz-83 because the average atomic mass of Gz is closer to 83.

The average atomic mass is defined as the weigthed mean of the isotopes.

The mass of the isotopes is 80, 81 and 83 uma, respectively.

As the average atomic mass (82.74uma) is closer to the atomic mass of Gz-83 than the mass of the other isotopes, you can interpretate that the most abundant isotope is Gz-83.

Learn more about average atomic mass in:

brainly.com/question/21536220

5 0
2 years ago
What happens to the electrons in an ionic bond?
Anton [14]

Answer:

In an ionic bonds, the metal loses electrons to become a positively charged cation, In which the nonmetal accepts those electrons to become a negatively charged anion.

Explanation:

3 0
3 years ago
Read 2 more answers
1-propanol (P1° = 20.9 Torr at 25 °C) and 2-propanol (P2° = 45.2 Torr at 25 °C) form ideal solutions in all proportions. Let x1
jekas [21]

Answer:

y1 = 0.3162

y2 = 0.6838

Explanation:

ok let us begin,

first we would be defining the parameters;

at 25°C;

1-propanol P1° = 20.90 Torr

2-propanol P2° = 45.2 Torr

From Raoults law:

P(1-propanol) = P⁰ × X(1-propanol)

P(1-propanol) = 20.9 torr × 0.45 = 9.405

P(1-propanol) = 9.405 torr

Also P(2-propanol) = P⁰ × X(2-propanol)

P(2-propanol) = 45.2 torr × 0.45

P(2-propanol) = 20.34 torr

but the total pressure = sum of individual pressures

total pressure = 9.405 + 20.34

total pressure = 29.745 torr

given that y1 and y2 represent the mole fraction of each in the vapor phase

y1 = P1 / total pressure

y1 = 9.405/29.745

y1 = 0.3162

Since y1 + y2 = 1

y2 = 1 - y1

∴ y2 = 1 -  0.3162

y2 = 0.6838

cheers, i hope this helps.

7 0
3 years ago
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