Question

i don't need these solved I just need the steps to solve it and. what these problems in chemistry would be called so I can look up videos and extra work ​

Answer 1

The answers are as follows,

1. 4.71 L,

2. 3.29 L,

3. 1634.6 torr

Explanation:

All the above problems can be sorted out using the Boyle's law represents the relationship between the volume and pressure.

It can be expressed as follows,

                      P1V1 = P2V2

Rearranging the above expression, we get,

                     $V2 = \frac{P1V1}{V2}$

1) The first case can be solved as,

     $V 2=\frac{921 \mathrm{mm} \mathrm{Hg} \times 3.89 \mathrm{L}}{760 \mathrm{mm} \mathrm{Hg}}=4.71 \mathrm{L}$

2) The second case can be solved as,

       $V 2=\frac{25 L \times 600 \text { torr}}{4560 \text { torr}}=3.29 L$

3) The third case can be solved as,

     $P 2=\frac{7.43 L \times 1100 \text { torr}}{5 L}=1634.6 \text { torr}$

Thus the answers for all the three cases are found as,

1. 4.71 L,

2. 3.29 L,

3. 1634.6 torr respectively