Answer & Explanation:
volume of the block = 4.5 x 5 x 6 = 135 cm^3 also equal to 1.35 x 10^-4 m^3
USE THE FORMULA
<em>Density = mass / volume</em>
<em><u /></em>
<em><u>Answer in gcm^-3</u></em>
<em>Density = 1502 / 135</em>
<u>Density = 11.1 gcm^-3</u>
<em><u /></em>
<em><u>Answer in kgm^-3</u></em>
<em>Density = 1.502 / 1.35 x 10^-4</em>
<u>Density = 11125.9 kgm^-3</u>
Answer:
59.19%
Explanation:
Step 1:
Data obtained from the question. This include the following:
Input temperature = 495 K.
Output temperature = 293 K.
Efficiency =..?
Step 2:
Determination of the efficiency of the engine.
Efficiency is simply defined as the ratio of output to input times 100. Mathematically, it is expressed as:
Efficiency = output /input x 100
With the above formula, we can calculate the efficiency of the engine as follow:
Input temperature = 495 K.
Output temperature = 293 K.
Efficiency =..?
Efficiency = output /input x 100
Efficiency = 293/495 x 100
Efficiency = 59.19%
Therefore, the efficiency of the engine is 59.19%
Explanation:
Given parameters:
Jermaine runs exactly 2 laps around a 400m track
Start time = 3:02:00PM
End time = 3:04:45PM
Unknown:
Distance traveled = ?
Speed = ?
Displacement = ?
Velocity = ?
Solution:
To solve this problem, we need to find the distance and time first;
Distance = 2 x 400 = 800m
Time taken = 3:04:45PM - 3:02:00PM = 165s
Speed = = = 4.85m/s
The velocity of the body is 0m/s and so is the displacement.
This is because the starting and finishing position of the Jermaine is the same.
Answer:
Explanation:
F = ma. For us, this looks like
60 = 30a and
a = 2 m/s/s
If the force goes up to, say, 90, then
90 = 30a and
a = 3...if the force goes up, the acceleration also goes up.
If the mass goes up to say, 60, and the force stays the same, then
60 = 60a and
a = 1...if the mass goes up, the acceleration goes down.