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3 years ago

What is the chemical formula for an amino group?

1 answer:

4 0

Formula of the 20 common amino acids. The formula of an amino acid comprises, bound to a carbon (alpha carbon): a carboxyl group -COOH. an amine group -NH2.

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What is the hypothetical van't Hoff factor of magnesium nitrate, Mg(NO3)2?

vovangra [49]

Answer:

The hypothetical van't Hoff factor of magnesium nitrate, $Mg(NO_3)_2$ is 3 .

Explanation:

Lets calculate -

$Mg(NO_3)_2\rightarrow Mg^2^+ +2NO_3^-$

We know that ,

$i=\alpha n+(1-\alpha )$

Dissociation should be 100% for the hypothetical vant hoff factor , that is

$\alpha =1$ and $n=3$ for $Mg(NO_3)_2$

Therefore , putting the given values ,

$i=1\times3+(1-1 )$

$i=3+0$

$i=3$

Hence , the answer is 3.

4 0

3 years ago

A student builds a model of her bedroom. the scale is 1:25. in scale model, the students bed is 3 inches long

ad-work [718]

The answer is C 75 inches

8 0

3 years ago

What mass of oxygen reacts with 3.6 g of magnesium to form magnesium oxide?

levacccp [35]

Answer is: the mass of the oxygen is 2.37 grams.

Balanced chemical reaction: 2Mg + O₂ → 2MgO.

m(Mg) = 3.6 g; mass of magnesium.

n(Mg) = m(Mg) ÷ M(Mg).

n(Mg) = 3.6 g ÷ 24.3 g/mol

n(Mg) = 0.149 mol.; amount of the magnesium.

n(O₂) = ?

From chemical reaction: n(Mg) : n(O₂) = 2 : 1.

n(O₂) = n(Mg) ÷ 2.

n(O₂) = 0.149mol ÷ 2.

n(O₂) = 0.075 mol; amount of the oxygen.

m(O₂) = m(O₂) · M(O₂).

m(O₂) = 0.075 mol · 32 g/mol.

m(O₂) = 2.37 g; mass of the oxygen.

3 0

3 years ago

A 15.0-L scuba diving tank contains a helium-oxygen (heliox) mixture made up of 23.0 g of He and 4.14 g of O2 at 298 K. Calculat

EleoNora [17]

Answer: The mole fraction of Helium is 0.978 and that of oxygen gas is 0.022

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For helium:

Given mass of helium = 23 g

Molar mass of helium = 4 g/mol

Putting values in equation 1, we get:

$\text{Moles of helium}=\frac{23g}{4g/mol}=5.75mol$

For oxygen gas:

Given mass of oxygen gas = 4.14 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

$\text{Moles of oxygen gas}=\frac{4.14g}{32g/mol}=0.129mol$

Mole fraction of a substance is given by:

$\chi_A=\frac{n_A}{n_A+n_B}$

For helium:

Moles of helium = 5.75 moles

Total moles = [5.75 + 0.129] = 5.879 moles

Putting values in above equation, we get:

$\chi_{(He)}=\frac{5.75}{5.879}=0.978$

For oxygen gas:

Moles of oxygen gas = 0.129 moles

Total moles = [5.75 + 0.129] = 5.879 moles

Putting values in above equation, we get:

$\chi_{(O_2)}=\frac{0.129}{5.879}=0.022$

Hence, the mole fraction of Helium is 0.978 and that of oxygen gas is 0.022

3 0

3 years ago

Will hydrogen ever make a double bond?

Andrei [34K]

No, hydrogen can only hold one bond and that's it. It only needs to be paired with one bond.

7 0

3 years ago

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