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Verdich [7]
3 years ago
13

Suppose that you can throw a projectile at a large enough v0 so that it can hit a target a distance R downrange. Given that you

know v0 and R, determine the general expressions for the two distinct launch angles θ1 and θ2 that will allow the projectile to hit D. For v0 = 42 m/s and R = 70 m, determine numerical values for θ1 and θ2?

Physics
1 answer:
NikAS [45]3 years ago
7 0

Answer:

Theta1 = 12° and theta2 = 168°

The solution procedure can be found in the attachment below.

Explanation:

The Range is the horizontal distance traveled by a projectile. This diatance is given mathematically by Vo cos(theta) t. Where t is the total time of flight of the projectile in air. It is the time taken for the projectile to go from starting point to finish point. This solution assumes the projectile finishes uts motion on the same horizontal level as the starting point and as a result the vertical displacement is zero (no change in height).

In the solution as can be found below, the expression to calculate the range for any launch angle theta was first derived and then the required angles calculated from the equation by substituting the values of the the given quantities.

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Explanation:

Not enough information. It really depends on the technical details of the car ( the data provided is offering just the human factor of the reaction, not the time for getting the impulse through when using the breaks

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2 years ago
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A coil formed by wrapping 65 turns of wire in the shape of a square is positioned in a magnetic field so that the normal to the
Fiesta28 [93]

Answer:

377 m

Explanation:

number of turns, N = 65

θ = 36°

B1 = 200 micro Tesla

B2 = 600 micro tesla

t = 0.4 s

induced emf, e = 80 mV

Let a be the side of the square coil.

e=\frac{d\phi }{dt}=NA\frac{dB}{dt}\times Sinθ

0.080=\frac{65\times a^{2}\times Sin36\times\left ( 600 - 200 \right )\times 10^{-6}}{0.4}

0.080=0.038a^{2}

a = 1.45 m

Total length of the wire, L = N x 4a = 65 x 4 x 1.45 = 377 m

Thus, the length of the wire is 377 m.

7 0
3 years ago
Gauss's Law states that the net electric flux, , through any closed surface is proportional to the charge enclosed: . The analog
Natali [406]

The analogous formula for magnetic fields is the Ampere's law.

To find the answer, we need to know about the Ampere's law of magnetism.

<h3>What's Ampere's law of magnetism?</h3>

Ampere's law states that the close line integral of magnetic field around a current carrying loop is directly proportional to the current enclosed within it.

<h3>What's is the mathematical expression of Ampere's law?</h3>

Mathematically, Ampere's law is

B•dl= μ₀I

Thus, we can conclude that the analogous formula for gauss law is the Ampere's law in magnetism.

Learn more about the Ampere's law here:

brainly.com/question/17070619

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5 0
2 years ago
If points a and b are connected by a wire with negligible resistance, find the magnitude of the current in the 12.0 v battery.
Marizza181 [45]
V = I * R
Where V is the voltage, I is the current and R is the resistance. Using Ohm's law, you require resistance to find the current through the wire. Technically, if the wire has a resistance of 0, you will get infinite current. But this isn't possible. Maybe the negligible resistance refers to the battery's internal resistance - not the wire's resistance. 
7 0
2 years ago
. Two identical vehicles traveling at the same speed are made to collide with barriers in an insurance company collision test. T
Serggg [28]

Answer:

F₁ / F₂ = 10

therefore the first out is 10 times greater than the second barrier

Explanation:

For this exercise let's use the relationship between momentum and momentum.

         I = F t = Δp

in this case the final velocity is zero

        F t = 0 -m v₀

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in order to answer the question we must assume that the two vehicles have the same mass and speed

concrete barrier

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        F₁ = - 10 p₀

barrier collapses

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let's look for the relationship of the forces

        F₁ / F₂ = 10

therefore the first out is 10 times greater than the second barrier

5 0
2 years ago
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