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Verdich [7]
3 years ago
13

Suppose that you can throw a projectile at a large enough v0 so that it can hit a target a distance R downrange. Given that you

know v0 and R, determine the general expressions for the two distinct launch angles θ1 and θ2 that will allow the projectile to hit D. For v0 = 42 m/s and R = 70 m, determine numerical values for θ1 and θ2?

Physics
1 answer:
NikAS [45]3 years ago
7 0

Answer:

Theta1 = 12° and theta2 = 168°

The solution procedure can be found in the attachment below.

Explanation:

The Range is the horizontal distance traveled by a projectile. This diatance is given mathematically by Vo cos(theta) t. Where t is the total time of flight of the projectile in air. It is the time taken for the projectile to go from starting point to finish point. This solution assumes the projectile finishes uts motion on the same horizontal level as the starting point and as a result the vertical displacement is zero (no change in height).

In the solution as can be found below, the expression to calculate the range for any launch angle theta was first derived and then the required angles calculated from the equation by substituting the values of the the given quantities.

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Which will increase the kinetic energy of an object more, increasing its mass or increasing its speed? Why?
agasfer [191]
Increasing its velocity will add to the kinetic energy more as the formula for kinetic energy is 0.5*m*v^2. (The speed will be squared making it greater)
4 0
3 years ago
Is 250 000 miles from the earth to the moon" is a qualitative<br> Observation<br> TRUE<br> Or false
lys-0071 [83]

Answer:

True

Explanation:

3 0
3 years ago
Please help! I'm not sure what equation or the process to do this question.
lions [1.4K]

Answer:

The momentum is 1.94 kg m/s.

Explanation:

To solve this problem we equate the potential energy of the spring with the kinetic energy of the ball.

The potential energy U of the compressed spring is given by

U = \dfrac{1}{2} kx^2,

where x is the length of compression and k is the spring constant.

And the kinetic energy of the ball is

K.E = \dfrac{1}{2}mv^2.

When the spring is released all of the potential energy of the spring goes into the kinetic energy of the ball; therefore,

\dfrac{1}{2}mv^2 = \dfrac{1}{2}kx^2,

solving for v we get:

v = x \sqrt{\dfrac{k}{m} }.

And since momentum of the ball is p=mv,

p =mx \sqrt{\dfrac{k}{m} }.

Putting in numbers we get:

p =(0.5kg)(0.25m) \sqrt{\dfrac{(120N/m)}{0.5kg} }.

\boxed{p=1.94kg\: m/s}

5 0
2 years ago
Rx: hydrochloric acid 2 percent solution 500 ml. your stock solution of hydrochloric acid is 10 percent. how much of the stock s
Allisa [31]

100 ml

100 ml of the stock solution is required to prepare the order.

We know that C1V1 = C2V2

where C1= 2%

V1 = 500ml

C2= 10%

V2 = ?

V2 = C1V1 / C2

     = 500 * 2% / 10%

     =100

V2 = 100 ml

<h3>What is meant by stock solution?</h3>
  • A stock solution is a sizable amount of a typical reagent in a standardized concentration, like sodium hydroxide or hydrochloric acid.
  • This phrase is frequently used in analytical chemistry while doing operations like titrations where it's crucial to employ precise solution concentrations.
<h3>What distinguishes a standard solution from a stock solution?</h3>
  • The main distinction between stock solution and standard solution is that the former is a highly concentrated solution while the later is a solution whose concentration is precisely known.
  • Because standard solutions frequently arrive as stock solutions, the phrases "stock solution" and "standard solution" are connected.

To learn more about stock solution preparation visit:

brainly.com/question/14667249

#SPJ4

8 0
2 years ago
The resistance of a wire depends upon the material's resistivity and the length and cross‑sectional area of the wire. What will
andriy [413]

Answer:

R' = 4R

The resistance will become 4 times the initial value.

Explanation:

The resistance of a wire at room temperature, is given by the following formula:

R = ρL/A   ----------- equation 1

where,

R = Resistance of wire

ρ = resistivity of the material

L = Length of wire

A = Cross-sectional area of wire

Now, if the length (L) is multiplied by 4, then resistance will become:

R' = ρ(4L)/A

R' = 4 (ρL/A)

using equation 1:

<u>R' = 4R</u>

<u>The resistance will become 4 times the initial value.</u>

6 0
3 years ago
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