I believe the answer would be Kinetic Energy. Kinetic energy is defined as energy which a body possesses by virtue of being in motion. We weren’t given answer choices so I don’t have much to work with lol.
Every object will remain at rest
Answer:
The bikers speed at the top of other hill is <u>25.82 m/s.</u>
Explanation:
Considering the biker is riding on a frictionless surface.
∴ There is no non-conservative or external force acting on the biker.
Hence we can conserve the energy of biker and bike as a system.
Let,
= 44m
= 10m
Since the biker starts from rest , his initial speed
= 0 m/s
Let final speed of the bike at the top of other hill be
.
∴ Initial Energy (at the top of 44m hill) = 
Final Energy (at the top of 10m hill) =
.
Conserving both the energies , we get
= 
∴ 
Substituting the values for g ,
,
, we get
= 25.82 m/s
Answer:
a) 15.78 mi/h/s
b) 7.105 m/s^2
Explanation:
a) It is given that speed changes from 0 to 60 miles per hour (mph)
Acceleration is equal to change in speed divided by time
mi/h/s
b)
1 mile/h = 0.45 m/s
Acceleration in m/s^2
m/s^2
Answer:
v2f = +15.8 m/s
Explanation:
Conservation law of linear momentum:
m1v1i + m2vi2 = m1v1f + m2v2f
Given:
m1 = 1.1 × 10^3 kg
m2 = 2.3 × 10^3 kg
v1i = +22.0 m/s
v2i = 0
v1f = -11.0 m/s
v2f = ?
Re-arranging the conservation law, we get
m1v1i = m1v1f + m2v2f
Solving for v2f,
m2v2f =m1(v1i - v1f)
or
v2f = m1(v1i - v1f)/m2
= (1.1 × 10^3 kg)(22.0 m/s - (-11.0 m/s))/(2.3 m/s)
= (1.1 × 10^3 kg)(33.0 m/s)/(2.3 × 10^3 kg)
= +15.8 m/s