1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sveta_85 [38]
3 years ago
12

Weight is the amount of matter in an object. True or False

Physics
2 answers:
iVinArrow [24]3 years ago
6 0

Answer: False

Explanation: mass is the amount of matter in an object

natali 33 [55]3 years ago
4 0

Answer:

False

Explanation:

The mass of an object is normally known as the weight of the object. but mass is the amount of matter in the object. Weight is the force exerted on an object by gravity

You might be interested in
Please help me with this question​
Oksanka [162]

Car at rest:

velocity= 0m/s

Acceleration:

0.2m/s²

Since total time:

3 min = 180s

Formula of acceleration:

acceleration = [final velocity - initial velocity] ÷ [total time]

Velocity at end:

0.2m/s² = [final velocity - 0m/s] ÷ [180s]

0.2m/s² × 180s = [final velocity]

[final velocity] = 36m/s

Distance travelled:

Velocity = displacement(distance) ÷ time

36m/s = displacement(distance) ÷ 180s

displacement(distance) = 36m/s × 180s

displacement(distance) = 6480m

<em><u>Hey I'm sorry but i do not understand why the answer on your worksheet for distance travelled is 3240m... its </u></em><em><u>half</u></em><em><u> of what my answer is...</u></em>

6 0
2 years ago
I need help please so fast
Simora [160]

Answer:

DUumb

Explanation:

Duumb

7 0
3 years ago
A circuit has two 4Ω resistors in series with each other. What is the total resistance?
Paha777 [63]

Answer: 8Ω

Explanation:

Since there are two resistors of 4Ω

connected in series, the total resistance (Rtotal) of the circuit is the sum of each resistance.

i.e Rtotal = R1 + R2

R1 = 4Ω

R2 = 4Ω

Rtotal = ?

Rtotal = 4Ω + 4Ω

Rtotal = 8Ω

Thus, the total resistance of the circuit is 8Ω

3 0
3 years ago
How fast would you say the earth rotates near the equator?
PtichkaEL [24]
460 meters per second, or about 1,000miles per hour.
8 0
3 years ago
A uniform electric field is directed parallel to the +y axis. If a positive test charge begins at the origin and moves upward al
lukranit [14]

Answer: option 1 : the electric potential will decrease with an increase in y

Explanation: The electric potential (V) is related to distance (in this case y) by the formulae below

V = kq/y

Where k = 1/4πε0

Where V = electric potential,

k = electric constant = 9×10^9,

y = distance of potential relative to a reference point, ε0 = permittivity of free space

q = magnitude of electronic charge = 1.609×10^-19 c

From the formulae, we can see that q and k are constants, only potential (V) and distance (y) are variables.

We have that

V = k/y

We see the potential(V) is inversely proportional to distance (y).

This implies that an increase in distance results to a decreasing potential and a decrease in distance results to an increase in potential.

This fact makes option 1 the correct answer

3 0
3 years ago
Other questions:
  • If one ammeter read 2a what would the other one read
    8·1 answer
  • What is refractive index​
    12·1 answer
  • For number 1 I'm really confused
    6·2 answers
  • What happens to the change in the value of the speed as you increased the amount of force applied on your
    5·1 answer
  • A car moving eastward along a straight road increases its speed uniformly from 16 m/s to 32 m/s in 10.0 s.
    13·1 answer
  • 4. What is the amplitude of the waves shown in the diagram below?
    10·1 answer
  • The images formed by convex mirrors are always in which form ​
    9·2 answers
  • Give the names of two animals which reproduce sexually​
    9·1 answer
  • How will you show that white light is made of several colours?
    9·1 answer
  • Two astronauts of mass 100 kg are 2 m apart in outer space. What is the
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!