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3 years ago

Which of the following characteristics are displayed by hard magnetic materials?

Physics

1 answer:

irakobra [83]3 years ago

4 0

Answer:

Characteristics are displayed by hard magnetic materials:

B. relatively large hysteresis loop.

D. Magnetization and demagnetization require relatively high applied fields.

Explanation:

They are otherwise called as the permanent magnets, they have the ability to retain is quality even after being magnetised. They have the ability of greater hysteresis loop, it is the relation between the induced magnetic flux to that of magnetizing force. When it is high gives the hard magnetic material. They have high retentivity and coercivity. This means the driving field during magnetization is null. To get coercivity the driving field should be made in the opposite direction.

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3 years ago

If a current is two amps and the resistance is 3 ohms, how much voltage was needed?

Hunter-Best [27]

Answer:

6 V

Explanation:

We can solve the problem by using Ohm's law:

$V=RI$

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R is the resistance

I is the current

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3 years ago

Each plate of a parallel‑plate capacitor is a square of side 4.19 cm, 4.19 cm, and the plates are separated by 0.407 mm. 0.407 m

alexandr1967 [171]

Answer:

The electric field strength inside the capacitor is 49880.77 N/C.

Explanation:

Given:

Side length of the capacitor plate (a) = 4.19 cm = 0.0419 m

Separation between the plates (d) = 0.407 mm = $0.407\times 10^{-3}\ m$

Energy stored in the capacitor (U) = $7.87\ nJ=7.87\times 10^{-9}\ J$

Assuming the medium to be air.

So, permittivity of space (ε) = $8.854\times 10^{-12}\ F/m$

Area of the square plates is given as:

$A=a^2=(0.0419\ m)^2=1.75561\times 10^{-3}\ m^2$

Capacitance of the capacitor is given as:

$C=\dfrac{\epsilon A}{d}\\\\C=\frac{8.854\times 10^{-12}\ F/m\times 1.75561\times 10^{-3}\ m^2 }{0.407\times 10^{-3}\ m}\\\\C=3.819\times 10^{-11}\ F$