Answer:
fr ’= ½ F
Explanation:
For this exercise we use the translational equilibrium equation, on the axis parallel to the wall
fr - W = 0
fr = W
for the adult man they indicate that the friction force is equal to F
F = M g
we write the equilibrium equation for the child
fr ’= w’
fr ’= m g
in the statement they tell us that the mass of the adult is 2 times the mass of the child
M = 2m
we substitute
fr ’= M / 2 g
fr ’= ½ Mg
we substitute
fr ’= ½ F
therefore the force of friction in the child is half of the friction in the adult
Answer:
= 0.0050 M
= 0.0155 M
Explanation:
Initial moles of
= 0.072 mole
Volume of container = 3.9 L
Initial concentration of
The given balanced equilibrium reaction is,

Initial conc. 0.018 M 0
At eqm. conc. (0.018-x) M (2x) M
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[I]^2}{[I_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BI%5D%5E2%7D%7B%5BI_2%5D%7D)

we are given : 
Now put all the given values in this expression, we get :


So, the concentrations for the components at equilibrium are:
![[I]=2\times x=2\times 0.0025=0.0050](https://tex.z-dn.net/?f=%5BI%5D%3D2%5Ctimes%20x%3D2%5Ctimes%200.0025%3D0.0050)
![[I_2]=0.018-x=0.018-0.0025=0.0155](https://tex.z-dn.net/?f=%5BI_2%5D%3D0.018-x%3D0.018-0.0025%3D0.0155)
Hence, concentrations of
and
are 0.0050 M ad 0.0155 M respectively.
Answer:
Explanation:
- The volume of water displaced by immersing the object is equal the amount of water spilled and caught by Dr. Hewitt.
- The amount of water is proportional to the volume of object of fraction of object immersed in water will lead to the same fraction of water displaced and caught by Dr. Hewitt.
- When the object is immersed the force of Buoyancy acts against the weight and reducing the scale weight.
- The amount of Buoyancy Force is proportional to the fraction of Volume of object immersed in water; hence, the same amount is spilled/lost.