Question

A 26.5 g object is thrown straight up into the air. If the object's initial speed is 1.60 m/s, determine how high the object will rise.

Answer 1

Answer:

0.131 m

Explanation:

Applying,

v² = u²+2gh................... Equation 1

Where, v = final velocity, u = initial velocity, g = acceleration due to gravity, h =  maximum height of the object

make h the subject of the equation

h = (v²-u²)/2g........... Equation 2

From the question,

Given: v = 0 m/s (at the maximum height), u = 1.60 m/s

Constant: g = -9.8 m/s² (thrown up)

Substitute these values into equation 2

h = (0²-1.6²)/[2×(-9.8)]

h = -2.56/-19.6

h = 0.131 m