<u>169 Kcalories</u> are provided by a portion of food that has 25 grams of carbs, 6 grams of protein, and 5 grams of fat.
Kcalories mean kilo-calories. Basically, kilo-calorie or kcal refers to 1,000 calories. To get the Kcalories of food, you have to add the kcal of carbohydrates, protein, and fat.
Get the product by multiplying the number of grams of carbohydrate, protein, and fat by 4,4, and 9, respectively. So if you want to get the energy or Kcal available from a meal, you must then combine the outcomes.
Simply put it, take note of the following conversions:
- 1 gram of carbohydrate is 4kcal
- 1 gram of protein is also 4kcal
- Though, 1 gram of fat is 9kcal
So here's how to compute the Kcalories of food that contains 25g carbs, 6g protein, and 5g fat.
1. 25g x 4kcal/g = 100kcal
2. 6g x 4kcal/g = 24kcal
3. 5g x 9kcal/g = 45kcal
4. 100kcal + 24kcal + 45kcal = 169kcal!
Therefore, the food contains 169 kilo-calories!
You might be interested in nutrient density of an orange juice per kcalorie. Look here: brainly.com/question/26495283
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Answer:
a force that is able to act at a distance
Explanation:
:)
Answer: D. The elements have the same number of valence electrons
Explanation: The chemical reactivity of elements is governed by the valence electrons present in the element.
The elements present in the same group or vertical column have similar valence configurations and thus behave similarly in chemical reactions or have similar bonding properties.
For Example: Both fluorine and chlorine belong to same family or group and both have 7 electrons in their valence shell and thus accept single electron to attain noble gas configuration.
thus both would bond with a cation bearing a single positive charge.
Answer:
Explanation:
Examples are;
Ultraviolet light from sun.
Heat from a stove burner.
X-ray from an x-ray machine.
Alpha particle emit from a radio active decay of uranium.
Sound waves from your stereo.
Microwave from micro oven.
ultraviolet light from a black light.
Gamma radiations from a supernova.
AND MANY MORE.
Answer:
a) W = 46.8 J and b) v = 3.84 m/s
Explanation:
The energy work theorem states that the work done on the system is equal to the variation of the kinetic energy
W = ΔK = 
-K₀
a) work is the scalar product of force by distance
W = F . d
Bold indicates vectors. In this case the dog applies a force in the direction of the displacement, so the angle between the force and the displacement is zero, therefore, the scalar product is reduced to the ordinary product.
W = F d cos θ
W = 39.0 1.20 cos 0
W = 46.8 J
b) zero initial kinetic language because the package is stopped
W -
= -K₀
W - fr d= ½ m v² - 0
W - μ N d = ½ m v
on the horizontal surface using Newton's second law
N-W = 0
N = W = mg
W - μ mg d = ½ m v
v² = (W -μ mg d) 2/m
v = √(W -μ mg d) 2/m
v = √[(46.8 - 0.30 4.30 9.8 1.20) 2/4.3
]
v = √(31.63 2/4.3)
v = 3.84 m/s
