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krek1111 [17]
3 years ago
10

A 26.5 g object is thrown straight up into the air. If the object's initial speed is 1.60 m/s, determine how high the object wil

l rise.
Physics
1 answer:
fenix001 [56]3 years ago
8 0

Answer:

0.131 m

Explanation:

Applying,

v² = u²+2gh................... Equation 1

Where, v = final velocity, u = initial velocity, g = acceleration due to gravity, h =  maximum height of the object

make h the subject of the equation

h = (v²-u²)/2g........... Equation 2

From the question,

Given: v = 0 m/s (at the maximum height), u = 1.60 m/s

Constant: g = -9.8 m/s² (thrown up)

Substitute these values into equation 2

h = (0²-1.6²)/[2×(-9.8)]

h = -2.56/-19.6

h = 0.131 m

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Explanation:

Given

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Answer:

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Explanation:

Question

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For this case we want to write a expression for ma, and based on the previous info we can write:

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Answer:

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<u><em>Given:</em></u>

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