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nataly862011 [7]
3 years ago
12

The bowling ball is whizzing down the bowling lane at 4 m/s. If the mass of the bowling ball is 7 kg, what is its kinetic energy

?
Chemistry
1 answer:
natali 33 [55]3 years ago
4 0
KE = (1/2)(m)(v^2)

KE = (1/2)(7)(4^2)

KE = (1/2)(112)

KE = 56 J
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Combustion of ethylene glycol leads to a change in internal energy (\DeltaU) of –1189 kJ at 298 K. What is the corresponding cha
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Answer:

-1190.24 kJ

Explanation:

The enthalpy change in a chemical reaction that produces or consumes  gases is given by the expression:

ΔH = ΔU + Δngas RT

where  Δn gas is the change of moles of gas, R is the gas constant,and T is temperature.

Now from the given   balanced chemical reaction, the change in number of mol gas is equal to:

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Sionce we know ΔU and the temperature (298 K), we are in position to calculate the change in enthalpy.

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C1 Progress quiz: Atomic structure 2 - test
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0.11 nm

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A sample of a certain lead compound contains 12.92 g of lead for 2 g of oxygen. A second sample has mass of 34.27 g and contains
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The two chemical compounds are not the same, because their ratio is not equal. In both samples the composition of lead and oxygen is different.

<h3>What is a chemical compound?</h3>

A chemical compound is a substance made of numerous similar molecules (or molecular entities) joined by chemical bonds and comprising atoms from various chemical elements. Therefore, a molecule made up of only one type of atom is not a compound. Chemical reactions, which may entail interactions with other molecules, can change a compound into a distinct substance. Atomic bonds may be broken or new ones created during this process.

<h3>What are the calculations?</h3>

sample 1 = mass of lead / mass of oxygen = 12.92g/2g = 6.46 .

sample 2 = mass of lead/ mass of oxygen = 34.27 - 14.39/14.39 = 1.38 .

so, the ratios are not the same.

Hence, the two chemical compounds are not the same, because their ratio is not equal. In both samples the composition of lead and oxygen is different.

To know more about Chemical compounds, check out:

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