Answer:
The mass of the object would be 392. i hope this helps :)
Explanation:
Answer:82. Since you have a distance and a force, then the easiest principle to use is energy, i.e. work.
The work done by friction is F * d. This work cancels out the kinetic energy of the stone (1/2)mv^2
Fd = (1/2)mv^2
F = (1/2)mv^2/d.
Plug in m = 20 kg, v = 3 m/sec, d = 40 m.
83. With more mass, the kinetic energy is higher now. The work needed is higher. W = F * d and F is the same.
Explanation:Hope I helped :)
Answer:
the charge of each particular must be doubled
Explanation:
We can solve this exercise using Coulomb's law
F₀ = k q₁ q₂ / r²
tells us that the force is quadrupled and asks if the load
let's call the initial force F₀, let's find the force of the algae they double
q₁ = q₂ = 2q₀
we substitute
F = k 2q₀o 2q₀ / r₁2
F = 4 F₀
we see that for the force to multiply by 4, the charge of each particular must be doubled
C. 1.0 mol/kg sodium phosphide (Na3P)<span>
This is because it will produce 4 ions, and thus has the highest molalitiy. (more particles in solution lowers the freezing point)
</span><span>remember if you ever need anything and you dont want to waste points you can just post it on my pfp or message me the question</span>
Answer:
The orbital period of the planet would be half that of the earth
Explanation:
From the question we are told that
The mass of star is four times the mass of sun which can be mathematically represented as

Mathematically gravitational potential is given as

Where M is mass one
m is mass two
From this equation we see that the attraction force is directly proportional to the mass of the star
Thus we can say that
The centrifugal force that balances this attraction Force is

Where
is the centrifugal acceleration which can be mathematically represented as 
and m is the mass
Substituting this into the equation for centrifugal force

substituting into the equation above

Given that the diameter is the same and assuming that the mass is constant
Then


Take square root of both sides
