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Goshia [24]
4 years ago
9

Tory has a mass of 40kg. She sleds down a hill that has a slope of 25 degrees. what is the component of her weight that is along

her direction of motion?
Physics
1 answer:
Fudgin [204]4 years ago
3 0

1.7 x 10^2 N

or 166 N

First you find the vertical component of the weight, which is 9.8*40, (g*m), which is 392 N. You then find the angle between that and the slope, which is 90-25, which is 65. You then multiply the vertical weight by cos(65), to find the component of that that is parallel to the slope. You get 165.666 N

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Explanation:

A = 3m

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let the angle between the two vectors is θ.

the resultant of two vectors is given by

R=\sqrt{A^{2}+B^{2}+2ABCos\theta }

(a) R = 7 m

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(b) R = 1 m

So, 1=\sqrt{3^{2}+4^{2}+2\times 3\times 4 Cos\theta }

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