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OlgaM077 [116]
3 years ago
7

A monkey hangs motionless by one arm from a tree branch. Draw the free-body diagram.

Physics
1 answer:
Alexeev081 [22]3 years ago
7 0

Find the free-body diagram in attachment.

Explanation:

The free-body diagram of an object is a diagram representing all the forces acting on a body. Every force is represented using an arrow, where:

- The length of the arrow is proportional to the magnitude of the force

- The direction of the arrow shows the direction of the force

For the monkey in this problem, we have two forces acting on it:

- The weight of the monkey, labelled as (mg), acting downward, where

m is the mass of the monkey

g is the acceleration of gravity

- The tension in the tree branch, labelled as T, which acts upward

The monkey is motionless: this means that its acceleration is zero, so the net force actin on it is zero - this means that the forces acting on the monkey, the weight and the tension, are balanced, therefore they are shown as two arrows of same length, but opposite direction.

Learn more about forces and weight here:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

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In what way does the article contrast small cars with large cars?
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3 years ago
In Young’s two slit experiment, the first dark fringe above the central bright fringe occurs at an angle of 0.44˚. What is the r
melomori [17]

Answer:

d / λ = 26.7

Explanation:

In Young's double slit experiment, constructive interference is described by the expression

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In the case of destructive interference we must add half wavelength (λ/2)

   d siyn θ = (m + ½) λ

Let's clear

    d / λ = (m + ½) / sin θ

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2 years ago
A relaxed spring of length 0. 13 m stands vertically on the floor; its stiffness is 1180 N/m. You release a block of mass 0. 5 k
Daniel [21]

The length of spring when the block comes momentarily to rest on the compressed spring will be 0.054 m.The length of the spring by the letter x.

<h3>What is the potential energy of the spring?</h3>

The energy is stored in the spring when it is stretched or compressed by some length. It is the product of mass, gravity and distance compressed or stretched. Mathrmatically it is given by;

PE=mgh

The given data in the problem is ;

m is the mass of the block is 0.5 kg height,

h is the height is released is 0.7 m

x initial length of the spring = 0.13 m.

K is the force constant of the spring = 1180 N/m.

By the law of conservation of energy,

The potential energy of the spring gets converted

\rm mgh=\frac{1}{2}KL^2 \\\\ \rm L= \sqrt{\frac{2mgh}{K} } \\\\ \rm L= \sqrt{\frac{2\times 0.5\times9.81 \times 0.7}{1180} \\\\  \\\\

\rm L= 0.054m

Hence the length of spring when the block comes momentarily to rest on the compressed spring will be 0.054 m

To learn more about the potential energy of the spring refer to the link;

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