Answer:
175m
Explanation:
So it’s travelling at 35metres/1second so if we want to find 5 seconds we can do this…
35x5 ÷ 1 = 175m/5 seconds
The speed of light in that medium is 
.
<u>Explanation:</u>
It is known that the light's speed is constant when it travels in vacuum and the value is 
. When the light enters another medium other than vacuum, its speed get decreased as the light gets refracted by an angle.
The amount of refraction can be determined by the index of refraction or refractive index of the medium. The refraction index is measured as the ratios of speed of light in vacuum to that in the medium. It is represented as η = 
So, here η is the index of refraction of a medium which is given as 1.4, c is the light's speed in vacuum (
) and v is the light's speed in that medium which we need to find.
Thus the speed of light in that medium is 
Answer:
τ = 0.00203 seconds
Explanation:
The time constant τ in a R-L circuit is given by
τ = L/R
First we have to find out the equivalent resistance of the circuit.
Since there is a parallel combination of 19 Ω and 6.0 Ω resistor
Req = 19*6/19+6
Req = 4.56 Ω
Now we can find out the time constant
τ = L/R
τ = 0.0093/4.56
τ = 0.00203 seconds
Therefore, the time constant of this circuit is 0.00203 seconds.
I don't think that 4m has anything to do with the problem.
anyway. here.
A___________________B_______C
where A is the point that the train was released.
B is where the wheel started to stick
C is where it stopped
From A to B, v=2.5m/s, it takes 2s to go A to B so t=2
AB= v*t = 2.5 * 2 = 5m
The train comes to a stop 7.7 m from the point at which it was released so AC=7.7m
then BC= AC-AB = 7.7-5 = 2.7m
now consider BC
v^2=u^2+2as
where u is initial speed, in this case is 2.5m/s
v is final speed, train stop at C so final speed=0, so v=0
a is acceleration
s is displacement, which is BC=2.7m
substitute all the number into equation, we have
0^2 = 2.5^2 + 2*a*2.7
0 = 6.25 + 5.4a
a = -6.25/5.4 = -1.157
so acceleration is -1.157m/(s^2)
