Onlookers are often able to tell that a person who has been drinking alcohol has lost control of his faculties or behavior.

A long point-object, mass = 1.0 kg, moves in a circular path at a radial distance = 0.5 m from the axis of rotation. What is the

Vinvika [58]

Answer: $0.25\ kg-m^2$

Explanation:

Given

mass of Point object $m=1 kg$

Distance $r=0.5 m$

Since mass is moving in circular path therefore every time mass is at distance of r from center .

Also Moment of Inertia tells about the distribution of mass over the given region with respect to center of mass.

Therefore $I=mr^2$

$I=1\times 0.5^2$

$I=0.25\ kg-m^2$

5 0

3 years ago

What does a “fixed amount of fuel” mean?

klemol [59]

Answer:

A "fixed price" energy tariff means that your unit price for gas and electricity will not change for the duration of the plan. A variable rate means your energy price can vary during the plan. If you have a fixed price plan and your supplier announces a price rise, your rates will not change.

Explanation: Google

6 0

3 years ago

Read 2 more answers

Which of the following statements DOES NOT explicitly describe a transfer of money

kirill115 [55]

I think it’s c bc people get paid to drive others around the world

3 0

3 years ago

Read 2 more answers

2. Bianca stands on top of a tall building. She drops a 3 kg rock from rest. Ignoring air resistance, what will be the

Nataliya [291]

Answer:

v=-30 m/s

Explanation:

Using the equation:

v=u+at

v=?

u means initial velocity=0

a=-10 since it is going down we make the acceleration due to gravity negative

t=3

v=0+(-10)(3)

v=-30 m/s

6 0

3 years ago

A positron is an elementary particle identical to an electron except that its charge is . An electron and a positron can rotate

denis23 [38]

Explanation:

According to the energy conservation,

$F_{centripetal} = F_{electric}$

$\frac{mv^{2}}{r} = \frac{kq^{2}}{d^{2}}$

$v^{2} = \frac{kq^{2}r}{d^{2}m}$

= $\frac{9 \times 10^{9} N.m^{2}/C^{2} \times 1.6 \times 10^{-19} C \times 0.75 \times 10^{-9} m}{(1.50 \times 10^{-9}m)^{2} \times 9.11 \times 10^{-31} kg}$