Complete Question
A 10 gauge copper wire carries a current of 20 A. Assuming one free electron per copper atom, calculate the drift velocity of the electrons. (The cross-sectional area of a 10-gauge wire is 5.261 mm2.)
mm/s
Answer:
The drift velocity is 
Explanation:
From the question we are told that
The current on the copper is 
The cross-sectional area is
The number of copper atom in the wire is mathematically evaluated

Where
is the density of copper with a value 
is the Avogadro's number with a value 
Z is the molar mass of copper with a value 
So
Given the 1 atom is equivalent to 1 free electron then the number of free electron is

The current through the wire is mathematically represented as

substituting values

=> 
Answer: The correct answer for the blank is- Replication.
DNA replication is a biological process in which two identical replica of DNA are produced from single original DNA molecule through an enzyme called as DNA polymerase.
The two strands of double helical DNA are first separated ( with the help of helicase enzyme) so that the template DNA strands are exposed. In other words, the two strands are broken apart and attract new nucleotide bases to synthesize a new and complete strand of DNA.
This is done by DNA polymerase according to Watson and Crick base pairing ( A pairs to T, G pairs to C)
Answer: over burden is dissolved by water wind and acids
Answer:
the energy required for the extension is 12.25 J
Explanation:
Given;
force constant of trampoline spring, k = 800 N/m
extension of trampoline spring, x = 17.5 cm = 0.175 m
The energy required for the extension is calculated as;
E = ¹/₂kx²
E = 0.5 x 800 x 0.175²
E = 12.25 J
Therefore, the energy required for the extension is 12.25 J