Answer: It's the third one.
Explanation:
Answer:
Distance in pc= 20parsecs
Distance in zLY= 65.2LY
Distance in AU= 4.1×10^6AU
Explanation:
Using the formular:
d = 1/p
Where d = distance
P= parallax angle in arc of second
d= 1/0.050
d= 20 parsed
Converting to Lighy years,LY :
1 PC = 3.26LY
d= 20pc × (3.26Ly/1pc)
d= 65.2Ly
To convert to AU, 206,265 AU = 1pc
d= 20pc × (2.06×10^5AU/1pc)
d= 4.1×10^6AU
C.
It is a motion with uniform acceleration, meaning that the acceleration will not change.
The object is thrown upwards with a positive velocity. This shows that the upward direction is positive. The object will decelerate due to gravity at a magnitude of 9.81 m/s2. Therefore, the acceleration is -9.81 m/s2.
Note that even though the velocity of the object is momentarily 0 m/s at maximum height, there is still a constant acceleration.
This allows the object first decelerate upwards, then change direction at max height, and finally accelerate downwards. So in this case, the acceleration is always negative and unchanged.
Answer
given,
x = (3.9 cm)sin[(9.3 rad/s)πt]
general equation of displacement
x = A sin ω t
A is amplitude
now on comparing
c) Amplitude =3.9 cm
a) frequency =
f = 4.65 Hz
b) period of motion
T = 0.215 s
d) time when displacement is equal to x= 2.6 cm
x = (3.9 cm)sin[(9.3 rad/s)πt]
2.6 = (3.9 cm)sin[(9.3 rad/s)πt]
sin[(9.3 rad/s)πt] = 0.667
9.3 π t = 0.73
t = 0.025 s
Hello there.
<span>Which of the following scenarios would cause a sound to stop being produced?
</span><span>A. The vibration results in a molecule moving vertically.
</span>
