Answer:
∆H= <u>438 KJ/mol</u>
Explanation:
First, we have to find the <u>energy bond values</u> for each compound:
-) Cl-Cl = 243 KJ/mol
-) F-F = 159 KJ/mol
-) F-Cl = 193 KJ/mol
If we check the reaction we can calculate the <u>number of bonds</u>:
In total we will have:
-) Cl-Cl = 1
-) F-F = 3
-) F-Cl = 6
With this in mind. we can calculate the <u>total energy for each bond</u>:
-) Cl-Cl = (1*243 KJ/mol) = 243 KJ/mol
-) F-F = (3*159 KJ/mol) = 477 KJ/mol
-) F-Cl = (6*193 KJ/mol) = 1158 KJ/mol
Now, we can calculate the total energy of the <u>products</u> and the <u>reagents</u>:
Reagents = 243 KJ/mol + 477 KJ/mol = 720 KJ/mol
Products = 1158 KJ/mol
Finally, to calculate the total enthalpy change we have to do a <u>subtraction</u> between products and reagents:
∆H= 1158 KJ/mol-720 KJ/mol = <u>438 KJ/mol</u>
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I hope it helps!
Answer:
yes
Explanation:
The cell theory states that all biological organisms are composed of cells; cells are the unit of life and all life come from preexisting life. The cell theory is so established today that it forms one of the unifying principles of biology.
Answer:
U-238
Explanation:
For a given radioisotope, half life can be defined as the time taken for the isotope to decay into one-half of its original amount. Mathematically, this is expressed as:
where k = rate constant for the radioactive decay process
Greater the t1/2 longer will be its stability.
Based on the given data, U-238 has the largest half life and therefore will be best suited for applications mentioned.
The empirical formula for the citric acid is C₆H₈O₇
<h3>Data obtained from the question </h3>
Divide by their molar mass
C = 37.51 / 12 = 3.126
H = 4.2 / 1 = 4.2
O = 58.29 / 16 = 3.643
Divide by the smallest
C = 3.126 / 3.126 = 1
H = 4.2 / 3.126 = 1.34
O = 3.643 / 3.126 = 1.17
Multiply through by 6 to express in whole number
C = 1 × 6 = 6
H = 1.34 × 6 = 8
O = 1.17 × 6 = 7
Thus, the empirical formula for the citric acid is C₆H₈O₇
Learn more about empirical formula:
brainly.com/question/24818135
