When a solid with a mass of 53.78 g is added to 50.0 ml of water in a graduated cylinder, the volume increases to 56.4 ml. Calcu
1 answer:
You might be interested in
Answer:
0.43 grams is the maximum mass of sodium sulfate that could be produced by the chemical reaction.
Explanation:
Mass of sulfuric acid = 0.98 g
Moles of sulfuric acid =
Mass of sodium hydroxide = 0.240 g
Moles of sodium hydroxide =
According to reaction, 2 moles of sodium hydroxide reacts with 1 mole of sulfuric acid , then 0.0060 moles of sodium hydroxide will react with :
of sulfuric acid
As we can see that we have 0.010 moles of sulfuric acid but only 0.0030 moles of sulfuric acid will react which indicates that it is in excessive amount where as sodium hydroxide is in limiting amount.
So, amount of sodium sulfate to be formed will depend upon moles of sodium hydroxide.
According to reaction, 2 moles of sodium hydroxide gives with 1 mole of sodium sulfate , then 0.0060 moles of sodium hydroxide will give :
of sodium sulfate
Mass of 0.0030 moles of sodium sulfate :
0.0030 mol × 142 g/mol = 0.426 g ≈ 0.43 g
0.43 grams is the maximum mass of sodium sulfate that could be produced by the chemical reaction.
Answer:
Kc of reaction is 20.
Explanation:
The two proteins are X and Y.
The [X] = 1mM
[Y]=1mM
At equilibrium, [X] = 0.2mM [Y] = 0.2mM
we know that equilibrium constant is:
Kc=
[XY]= 1-0.20=0.80 mM
putting values:
Kc=