In the above word problem, If she chooses the 8-inch tiles, she will need a quarter as many tiles as she would with 2-inch tiles, Quarter 8-inch tiles will cover the same area as one 2-inches.
<h3>What is the justification for the above?</h3>
Note that the area of the one 2-inch tiles is given as:
A1 = 4in²
The area of the quarter 8-inch tiles is:
A2 = 1/4 x 8 x 8
A2 = 16inch²
Divide both areas
A2/A1= 16/4
= 4
This implies she'll need four 2-inch tiles to cover the same amount of space as a quarter 8-inch tile.
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Full Question:
A homeowner is deciding on the size of tiles to use to fully tile a rectangular wall in her bathroom that is 80 inches by 40 inches. The tiles are squares and come in three side lengths: 8 inches, 4 inches, and 2 inches. State if you agree with each statement about the tiles. Explain your reasoning.
If she chooses the 8-inch tiles, she will need a quarter as many tiles as she would with 2-inch tiles,
The volume of the rectangular prism is 3359232 cubic centimeters
<h3>How to determine the volume?</h3>
The length of the cube is given as:
Length, l = 12 cm
The volume of a cube is:
So, we have:
Evaluate
V = 1728
The volume of 1944 cubes is then calculated as:
Volume = 1728 * 1944
Evaluate
Volume = 3359232
Hence, the volume of the rectangular prism is 3359232 cubic centimeters
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<h3>Complete question</h3>
There are exactly 1,944 of the 12 cm, or 0.5 foot cubes inside a rectangular prism. What is the volume of the rectangular prism in cubic centimeters?
Answer:
a) Is it possible for Fred to accomplish this? Yes
b) If it is possible, what score does he need in his next game? 293
Step-by-step explanation:
Step 1
Let us represent the number of games Fred bowled to get an average of 177 = X
His total points scored in that game would be
177 × X
= 177X
To achieve an average of 178 for his next game,
The total number of points he scored was 199, hence that is represented as:
178 = 177X + 199/ X + 1
178(X + 1) = 177X + 199
178X + 178 = 177X + 199
178X - 177X = 199 - 178
X = 21
Hence, Fred bowled 21 games to achieve an average of 178
Therefore, the score he needs to have on the 23rd game is obtained as:
= (23 × 183) - (22 × 178) = 4209 - 3916 = 293
Therefore, it is possible for Fred to raise his average from 178 to 183 in a single game, but he must bowl 293 in his next game to do this.
Answer:
69cm
Step-by-step explanation:
Answer:
5/4
Step-by-step explanation:
