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Yuki888 [10]
3 years ago
13

Suppose a vacuum cleaner uses 120 J of electrical energy. If 45 J are used to pull air into the vacuum cleaner, how efficient is

the vacuum cleaner?
Physics
1 answer:
Zigmanuir [339]3 years ago
3 0
Efficiency = 45J/120J = 0.375

Or

0.375 * 100% = 37.5 %
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