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3 years ago

If an object with a mass of 12 kilograms is moving at 10 meters per second, what is its momentum?

Physics

1 answer:

ValentinkaMS [17]3 years ago

4 0

Answer:

120 kg.m/s

Explanation:

Momentum is defined as the product of mass and velocity of an object. Velocity in this case considers the direction of movement ie whether East to East or West etc. The formula for momentum is p=mv where p is momentum, m is the mass in kgs, v is the velocity in m/s. Substituting 12 kg for m and 10 m/s for v then momentum will be 12*10=120 kg.m/s

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What component of a longitudinal sound wave is analogous to a trough of a transverse wave?

anzhelika [568]

Explanation:

There are two components of a longitudinal sound wave which are compression and rarefaction. Similarly, there are two components of the transverse wave, the crest, and trough.

The crest of a wave is defined as the part that has a maximum value of displacement while the trough is defined as the part which corresponds to minimum displacement.

While compression is that space where the particles are close together while the rarefaction is that space where the particles are far apart from each other.

So, the refraction or the rarefied part of a longitudinal sound wave is analogous to a trough of a transverse wave.

6 0

3 years ago

What is the speed of a cyclist that rides west 88 km in 32 minutes?

suter [353]

Answer:

The speed of the cyclist is 2.75 km/min.

Explanation:

Given

The distance d = 88 km

Time t = 32 minutes

To determine

We need to find the speed of a cyclist.

In order to determine the speed of a cyclist, all we need to do is to divide the distance covered by a cyclist by the time taken to cover the distance.

Using the formula involving speed, time, and distance

$s=\frac{d}{t}$

where

s = speed

d = distance covered

t = time taken

substitute d = 88, and t = 32 in the formula

$s=\frac{d}{t}$

$s=\frac{88}{32}$

Cancel the common factor 8

$s=\frac{11}{4}$

$s=2.75$ km/min

Therefore, the speed of the cyclist is 2.75 km/min.

8 0

3 years ago

While performing an experiment involving a reaction between two chemicals, the scientist observes that the reaction container ha

AVprozaik [17]

When an object is becomes warm its an example of exothermic reaction.

8 0

3 years ago

As a stunt for movie two cars are to collide with each other head on. The two cars are initially 125 apart. Car A is heading str

Tema [17]

Answer:

3.39724 seconds

23.0824792352 m, 101.917520765 m

13.58896 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

The equation of motion will be

$s=ut+\dfrac{1}{2}at^2\\\Rightarrow 125=30\times t+\dfrac{1}{2}\times 4\times t^2\\\Rightarrow 2t^2+30t-125=0\ m$

$t=\frac{5\left(\sqrt{19}-3\right)}{2},\:t=-\frac{5\left(3+\sqrt{19}\right)}{2}\\\Rightarrow t=3.39724, -18.39724$

The time at which the cars collide is 3.39724 seconds

$s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 4\times 3.39724^2\\\Rightarrow s=23.0824792352\ m$

Car B traveled 23.0824792352 m and Car A traveled 125-23.0824792352 = 101.917520765 m

$v=u+at\\\Rightarrow v=0+4\times 3.39724\\\Rightarrow v=13.58896\ m/s$

The speed of car B is 13.58896 m/s

4 0

3 years ago

A fireman is standing on top of a building 19 m high, holding a firehose 1 m above the top of the building. She finds that if sh

DENIUS [597]

Answer:

A 2 d vector model

The acceleration function is -9.8 m/s2 which is gravity

Initial velocity on the Y axis is 0, on the X axis is 12 m/s

Inital position is 20 mts above the ground.

It takes the water 1.01 seconds to reach the other building.

THe distace from one building to the other is 12.11 meters.

Explanation:

In order to solve this you just need to carefully read the problem and the data you are given, and use the formula for height in free fall:

$h=\frac{1}{2} g*t^{2}$

So first the data, we know that the water is coming out at a height of 20 meters since the building is 19 meters tall and the fireman is holding the firehose 1 meter above it, and the water is hitting the second building at a height of 15 meters, that means that the water is travelin -5meters.

Gravity as it doesn´t say otherwise would be 9.8m/s2 since that is gravity on earth, and water is leaving the firehose at 12m/s horizontally.

We can calculate the time by using the height formula fro free fall:

$h=\frac{1}{2} g*t^{2}\\5=\frac{1}{2} 9.81*t^{2}\\t^{2}= \frac{10}{9.8} \\t^{2}=1.0193\\t=1.009 seconds$

So it takes 1.009 seconds for the water to frop from 20 to 15 meters, as the horizontal velocity remains the same we just multiply it by the time and we get the horizontal distance between the two buildings and that would be:

12.11 meters.

5 0

4 years ago