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3 years ago

If an object with a mass of 12 kilograms is moving at 10 meters per second, what is its momentum?

Physics

1 answer:

ValentinkaMS [17]3 years ago

4 0

Answer:

120 kg.m/s

Explanation:

Momentum is defined as the product of mass and velocity of an object. Velocity in this case considers the direction of movement ie whether East to East or West etc. The formula for momentum is p=mv where p is momentum, m is the mass in kgs, v is the velocity in m/s. Substituting 12 kg for m and 10 m/s for v then momentum will be 12*10=120 kg.m/s

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So, the best pressure is 110 GPa because 220 GPa, a 305 GPa and 360 GPa are the higher value of the maximum value 136 GPa of the lower mantle.

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3 years ago

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his is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Air enters a nozzle steadi

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Answer:

his is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Air enters a nozzle steadily at 2.21 kg/m3 and 40 m/s and leaves at 0.762 kg/m3 and 192 m/s. The inlet area of the nozzle is 90 cm2.

determine (a) the mass flow rate through the nozzle, and (b) the exit area of the nozzle.

a)0.7956kg/s

b)5.437 × 10⁻³m²

Explanation:

The concepts related to the change of mass flow for both entry and exit is applied

The general formula is defined by

$\dot{m}=\rho A V$

Where,

$\dot{m} = mass flow rate\\\rho = Density\\V = Velocity$

values are divided by inlet(1) and outlet(2) by

$\rho_1 = 2.21kg/m^3V_1 = 40m/s$

$A_1 = 90*10^{-4}m^2\\\rho_2 = 0.762kg/m^3\\V_2 = 192m/s$

PART A) Applying the flow equation

$\dot{m} = \rho_1 A_1 V_1\\\dot{m} = (2.21)(90*10^{-4})(40)\\\dot{m} = 0.7956kg/s$

PART B) For the exit area we need to arrange the equation in function of Area, that is

$A_2 = \frac{\dot{m}}{\rho_2 V_2}\\A_2 = \frac{0.7956}{(0.762)(192)}\\A_2 = 5.437*10^{-3}m^2$

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3 years ago

Which major planet has the largest . . . A. semimajor axis? B. average orbital speed around the Sun? C. orbital period around th

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<h2>Mercury, Neptune, and Jupiter </h2>

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Mercury has the largest semimajor axis that is 5.791 x 107 in km.
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Neptune has the longest orbital speed around the sun of any planet in the Solar System which is equivalent to 164.8 years (or 60,182 Earth days)
Jupiter has the largest eccentricity.

Hence, the answer is Mercury, Neptune, and Jupiter respectively.

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