The speed of the mass : <em><u>v = 0.316 m/s</u></em>
<h3>Further explanation</h3>
The energy used to press a spring is included as the potential energy
Can be formulated:
Ep= potential energy
k = spring constant
x = change in spring length
If the spring is released from its pressure, this potential energy will turn into kinetic energy
so applies the law of conservation of mechanical energy (Em)
Ek = Ep
A mass of 2 kg is attached to a spring, a spring constant of 20 N/m, and the spring is compressed 0.1 m past its natural length.
m = 2 kg
k = 20 N/m
x = 0.1 m
<h3>Learn more</h3>
Hooke's law
brainly.com/question/2648431
Keywords : spring,mass, spring constant,compressed position
The answers to your questions are as written below:
- The objects that represents a negatively charged particle is : Image B
- The object that represents a positively charged molecule is : Image A
- The object that represents an uncharged molecule is : Image C
- The object the will not move when in an electric fied is : Image C
<h3>Different types of charges molecules</h3>
A negatively charged molecule move inwards when placed in an electric field while positively charged molecule placed in a electric field will move outwards the electric field.
A neutral/uncharged molecule will remains still when placd in an elctric field due to the absence of charges.
Hence we can concude that the answers to your questions are as listed above.
Learn more about electric charges :brainly.com/question/857179
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attached below is the missing image
Answer: in this question, the only charge in the cavity is Q. Inside the conducting spherical shell, the electric field is zero.
While outside the shell, the electric field is given by: k(q + Q)/r²
Where;
K= is a constant which is given as, 8.99 x 10^9 N m² / C².
Q= source charge which creates the electric field
q= is the test charge which is used to measure the strength of the electric field at a given location.
r= is the radius
Explanation: Inside the conducting spherical shell, the electric field is zero since the Electric field vanishes everywhere inside the volume of a good conductor.
